Iphone 如何在NSURLConnection中的Json对象中发布xml？

嗨，我想在JSON对象中发布XML数据

这是我发帖的方式

[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
NSString *postString = [NSString stringWithFormat:@"{\"UserId\":\"%@\",\"UserDataXML\":\"%@\"}",@"USRfa9210bad85165d5",@"<Root Bookmark=\"Page1\">\\u000d\\u000a  <Name>MyName<\Name>\\u000d\\u000a <Address>MyAddress<\ Address></Root>"];
NSData  *requestData =  [postString dataUsingEncoding:NSUTF8StringEncoding];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-length"];
[request setHTTPBody:requestData];

---

首先，在使用之前必须先转义JSON

然后呢,

（1） 如果服务器仅使用表单数据进行响应，则post数据必须是一对键和值

NSString *postString = [NSString stringWithFormat:@"UserId=%@&UserDataXML=%@",
    @"USRfa9210bad85165d5",
    @"<Root Bookmark=\\\"Page1\\\">\\u000d\\u000a<Name>MyName</Name>\\u000d\\u000a<Address>MyAddress</Address></Root>"];

NSString*postString=[NSString stringWithFormat:@“UserId=%@&UserDataXML=%@”，
@“USRfa9210bad85165d5”，
@“\\u000d\\u000aMyName\\u000d\\u000aMyAddress”]；

（2） 如果服务器仅使用JSON响应，则内容类型应设置为“application/JSON”，然后

NSString *postString = [NSString stringWithFormat:@"{\"UserId\":\"%@\", \"UserDataXML\":\"%@\"}",
    @"USRfa9210bad85165d5",
    @"<Root Bookmark=\\\"Page1\\\">\\u000d\\u000a<Name>MyName</Name>\\u000d\\u000a<Address>MyAddress</Address></Root>"];

NSString*postString=[NSString-stringWithFormat:@“{\“UserId\”：\“%@\”，\“UserDataXML\”：\“%@\”}，
@“USRfa9210bad85165d5”，
@“\\u000d\\u000aMyName\\u000d\\u000aMyAddress”]；

顺便说一句，你检查过变量“_responseData”了吗？我想它也是空的

NSString *postString = [NSString stringWithFormat:@"{\"UserId\":\"%@\", \"UserDataXML\":\"%@\"}",
    @"USRfa9210bad85165d5",
    @"<Root Bookmark=\\\"Page1\\\">\\u000d\\u000a<Name>MyName</Name>\\u000d\\u000a<Address>MyAddress</Address></Root>"];