Iphone 如何确保字符串仅包含a–z和a–z字符？

我正在输入用户的名称，我只需要输入a-z和a-z。我想验证名称，请帮助我

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提前感谢

您可以这样做：

NSCharacterSet *allowed = [NSCharacterSet alphanumericCharacterSet];
NSCharacterSet *forbidden = [allowed invertedSet];
NSRange range = [string rangeOfCharacterFromSet:forbidden];
BOOL isValid = (range.location == NSNotFound);

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alphanumericCharacterSet可能不是您想要的，有关更多选项，请参阅NSCharacterSet。

您可以执行以下操作：

NSCharacterSet *allowed = [NSCharacterSet alphanumericCharacterSet];
NSCharacterSet *forbidden = [allowed invertedSet];
NSRange range = [string rangeOfCharacterFromSet:forbidden];
BOOL isValid = (range.location == NSNotFound);

NSCharacterSet *nonAlphabetChars = [[NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
if ([myString rangeOfCharacterFromSet:nonAlphabetChars].location == NSNotFound) {
    // myString is valid
    ...
} else {
    // myString contains at least one invalid character
    ...
}

alphanumericCharacterSet可能不是您想要的，有关更多选项，请参见NSCharacterSet

NSCharacterSet *nonAlphabetChars = [[NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
if ([myString rangeOfCharacterFromSet:nonAlphabetChars].location == NSNotFound) {
    // myString is valid
    ...
} else {
    // myString contains at least one invalid character
    ...
}