冒泡出一个异常：Java

因此，我有一个方法，如果发生异常，我希望在该方法中重试该操作。如果该异常再次发生，我希望在另一个类调用该方法的地方捕获该异常。这是正确的方法吗

    public OAuth2AccessToken getAccessTokenWithRefreshToken  (String refreshToken) throws OAuth2AccessTokenErrorResponse, IOException, InterruptedException ,ExecutionException  {
    try {
        System.out.println("trying for the first time");
        OAuth2AccessToken mAccessToken = mOAuthService.refreshAccessToken(refreshToken);
        return mAccessToken;
     catch (IOException | InterruptedException | ExecutionException e) {
        try {
            System.out.println("trying for the second time");
            OAuth2AccessToken mAccessToken = mOAuthService.refreshAccessToken(refreshToken);
        }  catch (IOException | InterruptedException | ExecutionException e2) {
            // TODO Auto-generated catch block
            e2.printStackTrace();
            throw e2;
        }
    }
    return mAccessToken;
}

---

为了避免重复，最好使用循环：

public OAuth2AccessToken getAccessTokenWithRefreshToken  (String refreshToken) throws OAuth2AccessTokenErrorResponse, IOException, InterruptedException ,ExecutionException {
    int maxAttempts = 2;
    int attempt = 0;
    while (attempt < maxAttempts) {
        try {
            return mOAuthService.refreshAccessToken(refreshToken);
        }
        catch (IOException | InterruptedException | ExecutionException e) {
            attempt++;
            if (attempt >= maxAttempts) {
                throw e;
            }
        }
    }
    return null; // or throw an exception - should never be reached
}

public OAuth2AccessToken getAccessTokenWithRefreshToken（字符串refreshToken）抛出OAuth2AccessTokenErrorResponse、IOException、InterruptedException、ExecutionException{
int=2；
int尝试=0；
while（尝试<最大尝试）{
试一试{
返回mOAuthService.refreshAccessToken（refreshToken）；
}
捕获（IOException | InterruptedException | ExecutionException e）{
尝试++；
如果（尝试次数>=最大尝试次数）{
投掷e；
}
}
}
返回null；//或引发异常-永远不应到达
}