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Java MonitorRequestWrapper是什么意思?为什么我不能从请求中获取参数?_Java_Javascript_Servlets - Fatal编程技术网

Java MonitorRequestWrapper是什么意思?为什么我不能从请求中获取参数?

Java MonitorRequestWrapper是什么意思?为什么我不能从请求中获取参数?,java,javascript,servlets,Java,Javascript,Servlets,我在Netbeans IDE中工作,我编写了向服务器发送HTTP请求的JS代码: function applyFilter(){ idFilterJS = getRadioValue(); var url = "applyfilter?action=applyfilterXML&id=" + idFilterJS; req = initRequest(); req.open("GET", url, true);

我在Netbeans IDE中工作,我编写了向服务器发送HTTP请求的JS代码:

function applyFilter(){
        idFilterJS = getRadioValue();
        var url = "applyfilter?action=applyfilterXML&id=" + idFilterJS;
        req = initRequest();
        req.open("GET", url, true);
        req.onreadystatechange = applyFilterCallBack;
        req.send(null);
    }
接下来,我在ApplyFilterServlet中有一个断点:

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        session = request.getSession();
        String action = request.getParameter("action");
}
我有两个问题:

在调试模式下,MonitorRequestWraper对于请求变量意味着什么? request.getParameteraction;返回null。为什么?
谢谢

它扩展了请求。深入“继承”下的属性以查找您的属性。
公共类MonitorRequestWrapper扩展了HttpServletRequestWrapper

在注释中添加建议