Java：调用类变量并在主变量中为其赋值

我有一个类和一个公共类，并希望从该类中分配一个变量，该类包含用户在公共类中输入的数据。是否可以这样做，或者我必须移动变量

这是我的密码

import java.util.Scanner;

class People {
    String name;
    int age;
    String hair_colour;
    String personality;

    void confirm(){
        System.out.println(name +" is " + age + " years old and has " 
            + hair_colour + " hair and has a " + personality +" personality");
        System.out.println("Is this correct? Y/N");
        Scanner correct = new Scanner(System.in);
        String reply = correct.nextLine();
        if(reply=="Y" || reply=="y"){
            System.out.println("Profile confirmed. Thank you.");
        }
        else {
            System.out.println("Returning to profile creation");
        }
    }
}

public class PeopleProfile {

    public static void main(String[]args){
        Scanner input_details = new Scanner(System.in);
        System.out.println("Please enter a name: ");
        String given_name = input_details.nextLine();
        System.out.println("Please enter a age: ");
        int given_age = input_details.nextInt();
        System.out.println("Please enter the persons hair colour: ");
        String given_hair_colour = input_details.nextLine();
        System.out.println("Please enter the persons personality: ");
        String given_personality = input_details.nextLine();
    }
}

---

您可以通过为此特定变量创建一个

设置器

来指定该变量

比如说你的财产

String hair_colour;

应采用以下方法

public void setHairColour(string hair_colourIn) {
   hair_colour = hair_colourIn;
}

您将调用此属性作为其类中的任何其他方法

People people = new People(); 
people.setHairColour(-your input string -)

要从其他类获取值，需要一个

getter

在给定的示例属性

头发颜色
中，应如下所示：

public string getHairColour() {
   return hair_colour;
}

所以你最终会：

People people = new People(); 
string hairColour = people.getHairColour();

您不能为您的人员类重载构造函数吗？

看起来是这样的：

class People {
String name;
int age;
String hair_colour;
String personality;

public People(String name, int age, String hair_colour, String personality){
    this.name = name;
    this.age = age;
    this.hair_colour = hair_colour;
    this.personality = personality;
}

void confirm(){
    System.out.println(name +" is " + age + " years old and has " + hair_colour + " hair and has a " + personality +" personality");
    System.out.println("Is this correct? Y/N");
    Scanner correct = new Scanner(System.in);
    String reply = correct.nextLine();
    if(reply.equals("Y") || reply.equals("y")){
        System.out.println("Profile confirmed. Thank you.");
    }
    else{
        System.out.println("Returning to profile creation");
    }
}
}

那么，在你的主体中，你可以这样称呼它：

public class PeopleProfile {
public static void main(String[]args){
    Scanner input_details = new Scanner(System.in);
    System.out.println("Please enter a name: ");
    String given_name = input_details.nextLine();
    System.out.println("Please enter a age: ");
    int given_age = input_details.nextInt();
    System.out.println("Please enter the persons hair colour: ");
    String given_hair_colour = input_details.nextLine();
    System.out.println("Please enter the persons personality: ");
    String given_personality = input_details.nextLine();
    People myPeople = new People(given_name, given_age, given_hair_colour, given_personality);
    myPeople.confirm();

}

试试这个：

import java.util.Scanner;

class People {
    String name;
    int age;
    String hairColour;
    String personality;

    void confirm() {
        System.out.println(name + " is " + age + " years old and has " + hairColour + " hair and has a " + personality + " personality");

        Scanner correct = new Scanner(System.in);

        System.out.println("Is this correct? Y/N");
        String reply = correct.nextLine();

        if ("Y".equals(reply) || "y".equals(reply)) {
            System.out.println("Profile confirmed. Thank you.");
        } else {
            System.out.println("Returning to profile creation");
        }
    }
}

public class PeopleProfile {
    public static void main(String[] args) {
        People boy = new People();
        Scanner inputDetails = new Scanner(System.in);

        System.out.println("Please enter a name: ");
        boy.name = inputDetails.nextLine();

        System.out.println("Please enter a age: ");
        boy.age = Integer.parseInt(inputDetails.nextLine());

        System.out.println("Please enter the persons hair colour: ");
        boy.hairColour = inputDetails.nextLine();

        System.out.println("Please enter the persons personality: ");
        boy.personality = inputDetails.nextLine();

        boy.confirm();
    }
}

您的代码要比按常规格式（理想情况下使用常规名称）更难阅读。此外，请参见。但请注意，目前您甚至没有创建
人员的实例
…为了澄清，我正在尝试为所有输入分配给定的名称（因为我在那里尝试调用名称时出错）等等。@Nathan没有人员的实例，就没有可分配的名称。您首先必须实例化一个人员对象，然后才能为该对象指定名称。切勿将字符串与==