Java 替换'的替代方法；线程。睡眠（5000）和#x27；

有没有替代“Thread.sleep（5000）”的方法？与目前一样，commentsbutton只单击一次，即使commentsbutton有其他元素，它也会转到CodesforRepliesButton？所以我认为可能是因为“Thread.sleep（5000）”页面没有加载完成

          if(commentsbutton.size() > 0) {
                commentsbutton.get(0).click(); //click on button if found
                Thread.sleep(5000); //pause for 5 seconds
          }           
          else clickMore = false;

          if(repliesbutton.size() > 0) {
                 repliesbutton.get(0).click(); //click on button if found
                 Thread.sleep(5000); //pause for 5 seconds
           }
           else clickMore = false; 

           if(seemorebutton.size() > 0) {
                  seemorebutton.get(0).click(); //click on button if found
                  Thread.sleep(5000); //pause for 5 seconds
           }
           else clickMore = false;
           }

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您可以为此使用循环，但必须了解，该循环将在执行期间使用流程资源。我想，在你的情况下，睡眠是最好的

          if(commentsbutton.size() > 0) {
                commentsbutton.get(0).click(); //click on button if found
                Thread.sleep(5000); //pause for 5 seconds
          }           
          else clickMore = false;

          if(repliesbutton.size() > 0) {
                 repliesbutton.get(0).click(); //click on button if found
                 Thread.sleep(5000); //pause for 5 seconds
           }
           else clickMore = false; 

           if(seemorebutton.size() > 0) {
                  seemorebutton.get(0).click(); //click on button if found
                  Thread.sleep(5000); //pause for 5 seconds
           }
           else clickMore = false;
           }

long now = System.currentMillisec();   
long executionDuration = now + 5000;
while(now < executionDuration){
    now = System.currentMillisec();
}

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“与目前一样，commentsbutton只单击一次，即使commentsbutton有其他元素，它也会转到codes for repliesbutton？”您需要使用循环。if else语句是否已经是循环？否，它不是循环。