Java Spring boot JPA相关实体说明
我有一个类似实体的流程,它将由一个用户创建、更新。当我尝试应用过滤器时。我已经在数据库中创建了外键关系。现在,当我使用JPA规范应用动态过滤器时,我得到的异常如下Java Spring boot JPA相关实体说明,java,spring,hibernate,jpa,Java,Spring,Hibernate,Jpa,我有一个类似实体的流程,它将由一个用户创建、更新。当我尝试应用过滤器时。我已经在数据库中创建了外键关系。现在,当我使用JPA规范应用动态过滤器时,我得到的异常如下 找不到为类型进程创建的属性 @Table(name = "process") @Entity public class Process { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = &quo
找不到为类型进程创建的属性代码>
@Table(name = "process")
@Entity
public class Process {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "PROCESS_ID")
@JsonProperty("id")
private Long id = null;
@NotNull
@Column(name = "NAME")
@JsonProperty("name")
private String name = null;
@Column(name = "CREATED_BY", updatable = false)
@JsonProperty("createdBy")
private Long createdBy = null;
@Column(name = "updatedBy", nullable = true)
@JsonProperty("updatedBy")
private Long updatedBy = null;
}
因此,我在流程实体中添加了实体关系映射,如下所示
现在,我得到下面的错误。我是JPA和hibernate新手,关系映射非常混乱,请帮助
@Table(name = "process")
@Entity
public class Process {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "PROCESS_ID")
@JsonProperty("id")
private Long id = null;
@NotNull
@Column(name = "NAME")
@JsonProperty("name")
private String name = null;
@Column(name = "CREATED_BY", updatable = false)
@JsonProperty("createdBy")
private Long createdBy = null;
@Column(name = "updatedBy", nullable = true)
@JsonProperty("updatedBy")
private Long updatedBy = null;
//newly added below properties so that there will be no error when fetching data
@OneToOne(targetEntity = UserDetails.class, fetch = FetchType.LAZY, mappedBy = "id")
private UserDetails CREATED;
@OneToOne(targetEntity = UserDetails.class, fetch = FetchType.LAZY, mappedBy = "id")
private UserDetails UPDATED;
}
现在,我得到下面的错误
在com.app.scenarios.domain.Process.CREATED的mappedBy中引用的属性不是一个(一个或多个)ToOne:com.app.users.details.domain.UserDetails.id
请让我知道我做错了什么。我有一个流程,可以由用户创建,也可以由用户更新。在DB中,我对process和userdetails实体具有外键关系
编辑
使用JPA规范从DB获取过滤数据的代码
Page result=this.processDao.findAll(getprocessGridData(processSearchCondition.getprocessName()),pageRequest)代码>
私有静态规范getprocessGridData(字符串processName){
返回(规范)(根、查询、准则生成器)->(
criteriaBuilder.like(root.get(“name”)、processName)
);
}
我想你真正想要的是:
@Table(name = "process")
@Entity
public class Process {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "PROCESS_ID")
@JsonProperty("id")
private Long id;
@NotNull
@Column(name = "NAME")
@JsonProperty("name")
private String name;
@OneToOne(fetch = FetchType.LAZY)
@jOINColumn(name = "CREATED_BY", updatable = false)
private UserDetails createdBy;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "UPDATED_BY", nullable = true)
private UserDetails updatedBy;
}
当我使用JPA规范应用动态过滤器时
-请说明您是如何做到的?添加了使用JPA规范的代码。由于上述relationshop错误,应用程序未运行
@Table(name = "process")
@Entity
public class Process {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "PROCESS_ID")
@JsonProperty("id")
private Long id;
@NotNull
@Column(name = "NAME")
@JsonProperty("name")
private String name;
@OneToOne(fetch = FetchType.LAZY)
@jOINColumn(name = "CREATED_BY", updatable = false)
private UserDetails createdBy;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "UPDATED_BY", nullable = true)
private UserDetails updatedBy;
}