Java SAXParseException:尝试在Android上解析远程XML时出现意外标记
我试图从互联网上解析一个XML,并在一个简单的文本视图中显示它的一些数据。这是我的密码:Java SAXParseException:尝试在Android上解析远程XML时出现意外标记,java,android,xml,saxparser,saxparseexception,Java,Android,Xml,Saxparser,Saxparseexception,我试图从互联网上解析一个XML,并在一个简单的文本视图中显示它的一些数据。这是我的密码: public class MainActivity extends AppCompatActivity { TextView tv1; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setC
public class MainActivity extends AppCompatActivity {
TextView tv1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv1=(TextView)findViewById(R.id.textView1);
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
try {
String UTF8 = "utf-8";
URL url = new URL("http://pollenapps.com/AllergyAlertWebSVC/api/1.0/Forecast/ForecastForZipCode?Zipcode=02145&Affiliateid=9642&AppID=2.1.0&uid=6693636764.xml");
URLConnection urlConnection = url.openConnection();
//InputStream in = new BufferedInputStream(urlConnection.getInputStream());
//BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream(), StandardCharsets.UTF_8));
//InputStream in = new URL("http://pollenapps.com/AllergyAlertWebSVC/api/1.0/Forecast/ForecastForZipCode?Zipcode=02145&Affiliateid=9642&AppID=2.1.0&uid=6693636764.xml").openStream();
//getAssets().open("file.xml");
InputStream in = url.openStream();
//InputStream is2 = new FileInputStream(file);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
//Document doc = dBuilder.parse(new InputSource(new InputStreamReader(in, "UTF-8")));
Document doc = dBuilder.parse(in, "UTF-8");
//Document doc = dBuilder.parse(in);
Element element = doc.getDocumentElement();
element.normalize();
NodeList nList = doc.getElementsByTagName("allergyForecast");
for (int i=0; i<nList.getLength(); i++) {
Node node = nList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE) {
Element element2 = (Element) node;
tv1.setText(getValue("Day0", element2));
}
}
} catch (Exception e) {e.printStackTrace();}
}
private static String getValue(String tag, Element element) {
NodeList nodeList = element.getElementsByTagName(tag).item(0).getChildNodes();
Node node = nodeList.item(0);
return node.getNodeValue();
}
}
根据一些研究,解析器似乎无法判断XML文件的编码类型,因此我需要定义它。然而,我不知道如何定义它在这里。。。我试图定义“UTF-8”编码的尝试可以在注释掉的行中看到,但这些都不起作用。有什么建议吗
XML:
谢谢大家! 您在响应中获得的数据是json格式的,而不是xml格式的。当您从UrlOpenConnection获取inputStream时,url中的前缀
.xml
不是以xml形式获取数据,可以删除。
要查看您获得的数据,请执行以下操作:
String data = "";
while (in.available() > 0)
data += (char)in.read();
System.out.println(data);
结果是:{“过敏预测”:{“第0天”:4.1,“第1天”:3.7,“第2天”:4.6,“第3天”:1.4,“第4天”:2.9,…}
要解析日期,您可以使用Gson作为示例。解析元素的代码段:
JsonElement jelement = new JsonParser().parse(new InputStreamReader(in));
// or from readed from inputStream string:
// JsonElement jelement = new JsonParser().parse(data);
JsonObject jobject = jelement.getAsJsonObject();
jobject = jobject.getAsJsonObject("allergyForecast");
然后,您可以从jsonObject获得所需的值。
或者,如果您只需要xml,您可以检查API如何获得xml响应
JsonElement jelement = new JsonParser().parse(new InputStreamReader(in));
// or from readed from inputStream string:
// JsonElement jelement = new JsonParser().parse(data);
JsonObject jobject = jelement.getAsJsonObject();
jobject = jobject.getAsJsonObject("allergyForecast");