javajson解析与Jackson

javajson解析与Jackson,java,json,jackson,Java,Json,Jackson,我试图通过这里的玩具示例了解Jackson解析JSON的诀窍: JSON: { "name" : { "first" : "Joe", "last" : "Sixpack" }, "gender" : "MALE", "verified" : false, "userImage" : "Rm9vYmFyIQ==" } “原始”数据绑定片段有问题: 1 ObjectMapper mapper = new ObjectMapper(); // can reuse, share g

我试图通过这里的玩具示例了解Jackson解析JSON的诀窍:

JSON:

{
  "name" : { "first" : "Joe", "last" : "Sixpack" },
  "gender" : "MALE",
  "verified" : false,
  "userImage" : "Rm9vYmFyIQ=="
}
“原始”数据绑定片段有问题:

1 ObjectMapper mapper = new ObjectMapper(); // can reuse, share globally
2 Map<String,Object> userData = mapper.readValue(new File("user.json"), Map.class);
1 ObjectMapper mapper=new ObjectMapper();//可以在全球范围内重复使用、共享
2 Map userData=mapper.readValue(新文件(“user.json”)、Map.class);

“name”处的值是{first=Joe,last=Sixpack}。当然,原始数据绑定可以处理嵌套的JSON对象,但我不知道如何访问first和last的值。我做错了什么?

我知道已经很晚了,但我就是这样做的。请看下面

MainClass.java=

import java.io.IOException;
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;

 public class MainClass {

public static void main(String[] args) throws JsonParseException, JsonMappingException, IOException {

    String jsonStr = "{\r\n" + "  \"name\" : { \"first\" : \"Joe\", \"last\" : \"Sixpack\" },\r\n"
            + "  \"gender\" : \"MALE\",\r\n" + "  \"verified\" : false,\r\n"
            + "  \"userImage\" : \"Rm9vYmFyIQ==\"\r\n" + "}";

    ObjectMapper mapper = new ObjectMapper();

    EntityClass jsonObj = mapper.readValue(jsonStr, EntityClass.class);

    System.out.println(jsonObj.getName().getFirst());
    System.out.println(jsonObj.getName().getLast());
    System.out.println(jsonObj.getGender());
    System.out.println(jsonObj.getVerified());
    System.out.println(jsonObj.getUserImage() + "\n");

}
  public class EntityClass
  {
          private String verified;

private Name name;

private String userImage;

private String gender;

public String getVerified ()
{
    return verified;
}

public void setVerified (String verified)
{
    this.verified = verified;
}

public Name getName ()
{
    return name;
}

public void setName (Name name)
{
    this.name = name;
}

public String getUserImage ()
{
    return userImage;
}

public void setUserImage (String userImage)
{
    this.userImage = userImage;
}

public String getGender ()
{
    return gender;
}

public void setGender (String gender)
{
    this.gender = gender;
}

@Override
public String toString()
{
    return "ClassPojo [verified = "+verified+", name = "+name+", userImage = "+userImage+", gender = "+gender+"]";
}
}

EntityClass.java=

import java.io.IOException;
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;

 public class MainClass {

public static void main(String[] args) throws JsonParseException, JsonMappingException, IOException {

    String jsonStr = "{\r\n" + "  \"name\" : { \"first\" : \"Joe\", \"last\" : \"Sixpack\" },\r\n"
            + "  \"gender\" : \"MALE\",\r\n" + "  \"verified\" : false,\r\n"
            + "  \"userImage\" : \"Rm9vYmFyIQ==\"\r\n" + "}";

    ObjectMapper mapper = new ObjectMapper();

    EntityClass jsonObj = mapper.readValue(jsonStr, EntityClass.class);

    System.out.println(jsonObj.getName().getFirst());
    System.out.println(jsonObj.getName().getLast());
    System.out.println(jsonObj.getGender());
    System.out.println(jsonObj.getVerified());
    System.out.println(jsonObj.getUserImage() + "\n");

}
  public class EntityClass
  {
          private String verified;

private Name name;

private String userImage;

private String gender;

public String getVerified ()
{
    return verified;
}

public void setVerified (String verified)
{
    this.verified = verified;
}

public Name getName ()
{
    return name;
}

public void setName (Name name)
{
    this.name = name;
}

public String getUserImage ()
{
    return userImage;
}

public void setUserImage (String userImage)
{
    this.userImage = userImage;
}

public String getGender ()
{
    return gender;
}

public void setGender (String gender)
{
    this.gender = gender;
}

@Override
public String toString()
{
    return "ClassPojo [verified = "+verified+", name = "+name+", userImage = "+userImage+", gender = "+gender+"]";
}
}

Name.java=

  public class Name {
private String last;

private String first;

public String getLast() {
    return last;
}

public void setLast(String last) {
    this.last = last;
}

@Override
public String toString() {
    return "Name [last=" + last + ", first=" + first + "]";
}

public String getFirst() {
    return first;
}

public void setFirst(String first) {
    this.first = first;
} }
结果:- 乔 六包 男性 假的
Rm9vYmFyIQ=

该键(
名称
)的
对象是否为映射?只需使用这些键(第一个、最后一个)对其进行施放和访问。Jackson将不惜一切代价,而
name
的键将是
Map
。只要在
.get()
时强制转换它。@fge您是说key
name
的值吗?((Map)userData.get(“name”).get(“first”);谢谢你们+什么是实体类?你能不能也在代码中添加它。EntityClass是Json所有属性的getter&setter类。是的,我知道它是PoJo类,因为它没有发布在OP上,请将它添加为答案的一部分。