Warning: file_get_contents(/data/phpspider/zhask/data//catemap/2/spring/14.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Java 无法使用spring管理的EntityManager持久化数据_Java_Spring_Hibernate_Jpa - Fatal编程技术网

Java 无法使用spring管理的EntityManager持久化数据

Java 无法使用spring管理的EntityManager持久化数据,java,spring,hibernate,jpa,Java,Spring,Hibernate,Jpa,我再次需要您的帮助,我正在尝试将Hibernate+Spring集成到我的独立java应用程序中,但是数据库操作不起作用,但是entitymanager被注入,我通过调试进行了验证,因此我不确定我的代码/配置中缺少什么,我通过谷歌搜索做了一些研究,但没有找到解决我问题的方法。因此,我发布了我的代码/配置,以便有人能帮助我摆脱困境 实体类: package com.entity; import javax.persistence.Column; import

我再次需要您的帮助,我正在尝试将Hibernate+Spring集成到我的独立java应用程序中,但是数据库操作不起作用,但是entitymanager被注入,我通过调试进行了验证,因此我不确定我的代码/配置中缺少什么,我通过谷歌搜索做了一些研究,但没有找到解决我问题的方法。因此,我发布了我的代码/配置,以便有人能帮助我摆脱困境

实体类:

      package com.entity;

      import javax.persistence.Column;
      import javax.persistence.Entity;
      import javax.persistence.GeneratedValue;
      import javax.persistence.GenerationType;
      import javax.persistence.Id;
      import javax.persistence.Table;

      @Entity
      @Table(name = "employee")
      public class Employee {

               @Id
               @GeneratedValue(strategy =  GenerationType.AUTO)
               @Column(name = "EMP_ID")
               private Integer empoyeeId;

               @Column(name = "EMP_NAME")
               private String employeeName;

               public Integer getEmpoyeeId() {
                     return this.empoyeeId;
               }

               public void setEmpoyeeId(Integer empoyeeId) {
                     this.empoyeeId = empoyeeId;
               }

               public String getEmployeeName() {
                     return this.employeeName;
               }

               public void setEmployeeName(String employeeName) {
                   this.employeeName = employeeName;
               }
       }
道类

  package com.dao.impl;

  import javax.persistence.EntityManager;

  import com.dao.IEmployeeDao;
  import com.entity.Employee;

  public class EmployeeDao implements IEmployeeDao {

        private static final Logger LOGGER = 
                  LogManager.getLogger(EmployeeDao.class);

        @PersistenceContext(unitName = "testPU")
        private EntityManager em;

        @Override
        public Employee create(Employee aEmployee) {
           return this.em.merge(aEmployee);
        }

        @Override
        public Employee fetchEmployeeById(Integer aEmployeeId) {
         return this.em.find(Employee.class, aEmployeeId);
        }
  }
主要类别:

    package com.client;

    import org.apache.logging.log4j.LogManager;
    import org.apache.logging.log4j.Logger;
    import org.springframework.beans.BeansException;
    import org.springframework.context.ApplicationContext;
    import org.springframework.context.support.ClassPathXmlApplicationContext;

    import com.dao.IEmployeeDao;
    import com.entity.Employee;

    public class Client {
           private static final Logger LOGGER = LogManager.getLogger(Client.class);

           public static void main(String[] args) throws BeansException, 
                   Exception {
                   ApplicationContext applicationContext = new 
                   ClassPathXmlApplicationContext("applicationcontext.xml");
                   LOGGER.info("client invoked");
                   IEmployeeDao employeeDao =  
                   (IEmployeeDao)applicationContext.getBean("employeeDao");
                   Employee employee = new Employee();
                   employee.setEmployeeName("Suraj Kumar");
                   employee = employeeDao.create(employee);
                   employee =                        
                   employeeDao.fetchEmployeeById(employee.getEmpoyeeId());  
                   //getting null pointer here as employee is null

                   //       EntityManagerFactory emf = 
                           Persistence.createEntityManagerFactory("testPU");
                  //        EntityManager em = emf.createEntityManager();
                  //        em.getTransaction().begin();
                  //        EmployeeDao employeeDao = new EmployeeDao();
                  //        employeeDao.setEm(em);
                  //        Employee employee = new Employee();
                  //        employee.setEmployeeName("Suraj Kumar");
                  //        employee = employeeDao.create(employee);
                  //        employee = 
                    employeeDao.fetchEmployeeById(employee.getEmpoyeeId());
                  //        em.getTransaction().commit();
                  //        em.close();
                  //        emf.close();
          }
     }
使用上面的客户机代码,我在尝试按id获取employee时遇到null指针异常,因为调用create返回的employee返回null,该null断言记录未持久化

然而,当我通过注释上面未注释的代码和现在注释的代码关闭spring时,即当我只使用hibernate而不使用spring时,一切正常。我在下面提供了配置文件

applicationcontext.xml:

    <?xml version="1.0" encoding="UTF-8"?>
    <beans xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns:aop="http://www.springframework.org/schema/aop"
        xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-2.5.xsd ">
    <import resource="aspects.xml"/>

        <bean class="org.springframework.orm.jpa.support.
                     PersistenceAnnotationBeanPostProcessor"/>

        <bean id="myEmf" 
        class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
            <property name="persistenceUnitName" value="testPU"/>
        </bean>

        <bean id="employeeDao" class="com.dao.impl.EmployeeDao" />

    </beans>
persistence.xml

   <?xml version="1.0" encoding="UTF-8"?>
   <persistence xmlns="http://java.sun.com/xml/ns/persistence"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/persistence

   http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
          version="2.0">
   <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL">
   <provider>org.hibernate.ejb.HibernatePersistence</provider>
   <class>com.entity.Employee</class>
   <exclude-unlisted-classes>true</exclude-unlisted-classes>
   <properties>
      <property name="hibernate.connection.url" 
                value="jdbc:mysql://localhost:3306/dbname"/>
      <property name="hibernate.connection.driver_class" 
                value="com.mysql.jdbc.Driver"/>

      <property name="hibernate.dialect" 
                value="org.hibernate.dialect.MySQLDialect"/>
      <property name="hibernate.connection.username" value="user"/>
      <property name="hibernate.connection.password" value="password"/>
      <property name="hbm2ddl.auto" value="update"/>
      </properties>
  </persistence-unit>
  </persistence>
我也在使用方面,但我没有发布代码,因为我不确定它是否相关,因为我尝试关闭方面,即使我面临这个问题,在关闭aspects时发生了一件奇怪的事情,那就是没有得到null指针异常,而是从EntityManager类的find方法内部得到了另一个异常,这表明在这种情况下,dao类的create方法不返回null


有人能帮我一下吗?

看来你的交易没有兑现


尝试将@Transactional添加到EmployeeDao类中的方法中,或者更好地创建一个服务层来处理事务,并使用@Transactional注释它们的方法。我在dao类的创建方法中添加了@Transactional only,因为要获取的方法是只读方法,我仍然会得到空指针,除了多一点,我刚刚读到,我们使用tag来帮助spring识别基于注释的AOP,但在这种情况下,我得到一个异常消息java.lang.IllegalStateException:AnnotationTransactionAttributeSource仅在java 1.5及更高版本上可用,我使用的是java 7,但我仍在使用spring-2.5.5,这可能是这个异常的原因吗?可能我需要增加spring版本以支持java 7,我不确定我是否在正确的方向上徘徊?它起作用了,没有在事务中运行的方法是一个问题。还有一些其他的问题,正是因为这些问题,我面临着一些问题,但对于无法正常运行的操作来说,主要原因是缺少了我们的事务处理能力。所以我把你的答案标记为接受。有人能帮忙吗?