Java 使按钮数组不可见(发出提示)
我想做一个提示按钮,所以当我点击它时,我想从列表(答案列表)中删除两个按钮。现在我不知道怎么做,如何在按钮数组上创建for循环,这样我就可以使这个按钮不可见Java 使按钮数组不可见(发出提示),java,android,arrays,function,button,Java,Android,Arrays,Function,Button,我想做一个提示按钮,所以当我点击它时,我想从列表(答案列表)中删除两个按钮。现在我不知道怎么做,如何在按钮数组上创建for循环,这样我就可以使这个按钮不可见 public class ClassicMode extends Activity {//מהמשחק עצמו String pic;//תמונה של הדגל Button answer1;//תשובות Button answer2; Button answer3; Button ans
public class ClassicMode extends Activity {//מהמשחק עצמו
String pic;//תמונה של הדגל
Button answer1;//תשובות
Button answer2;
Button answer3;
Button answer4;
Button hint;
TextView guess;
TextView numOfGuess;
TextView score;
TextView scorenum;
DatabaseHandler db = new DatabaseHandler(this);
String fn;
Guesses G;
Bitmap bm;
Score s;
Button [] b = new Button[4];
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_second);
ActionBar actionBar = getActionBar();
actionBar.setDisplayHomeAsUpEnabled(true);
score =(TextView)findViewById(R.id.score);
scorenum =(TextView)findViewById(R.id.scorenum);
scorenum.setText(String.valueOf(s.score));
guess =(TextView)findViewById(R.id.guesses);
numOfGuess=(TextView)findViewById(R.id.numOfGuesses);
numOfGuess.setText(String.valueOf(Guesses.numOfGuesses));
hint =(Button)findViewById(R.id.hint);
Flags f = new Flags();
Random r = new Random();//הדגל שיבחר לשאלה
int num = r.nextInt(160);//Up
f = db.getFlag(num);//הצגת הדגל הרנדומלי שיצא
fn = f.getName().toString();
pic = f.getImage().toString();
pic_view(pic);//מעבר לפונקציה להשמת התמונה של הדגל במשחק
//מערך ארבע כפתורים כנגד ארבע תשובות
b[0] = (Button)findViewById(R.id.button1);
b[1] = (Button)findViewById(R.id.button2);
b[2] = (Button)findViewById(R.id.button3);
b[3] = (Button)findViewById(R.id.button4);
List<String>Answers=new ArrayList<String>();//מערך תשובות
Answers.add(f.getName().toString());//הוספת התשובה הנכונה
for(int i=1;i<4;i++)
{
num = r.nextInt(200);
String valToAdd1 = db.getFlag(num).getName().toString();
if(!Answers.contains(valToAdd1)){
Answers.add(valToAdd1);
}
}
/*num = r.nextInt(30);
Answers.add(db.getFlag(num).getName().toString());//הוספת 3 תשובות רנדומליות
num = r.nextInt(30);
Answers.add(db.getFlag(num).getName().toString());
num = r.nextInt(30);
Answers.add(db.getFlag(num).getName().toString());*/
Collections.shuffle(Answers);//ערבוב התשובות
for(int i=0;i<Answers.size();i++)
{
b[i].setText(Answers.get(i));//השמת התשובות מהמהערך למערך הכפתורים
}
}//end of OnCreat
注意:这是{大部分}伪代码 我建议保留两份单独的答案清单。您的Flag对象已包含正确答案。您需要一个列表来跟踪错误答案(这样我们就不必每次都循环检查每一项)。您还需要一个列表,其中列出了所有可以洗牌和显示的内容 我有点冒昧地把变量名改长了,这样它们就更清晰了
onCreate() {
...
btnHint.setOnClickListener(hintOnClickListener);
...
Flag f = db.getFlag(randomNum); // This is the real question & answer
List<String> wrongAnswers = new ArrayList<String>(3);
List<String> allAnswers = new ArrayList<String>(4);
// Loop 3 times for 3 random wrong answers
for (int i=0; i<=3; i++) {
randNum = r.nextInt(200);
String randWrongAnswer = db.getFlag(randNum).getName().toString();
if (! wrongAnswers.contains(randWrongAnswer)) {
wrongAnswers.add(randWrongAnswer);
}
}
allAnswers.add(f.getName().toString());
allAnswers.addAll(wrongAnswers);
Collection.shuffle(allAnswers);
...
}
onCreate(){
...
btnHint.setOnClickListener(hintOnClickListener);
...
Flag f=db.getFlag(randomNum);//这是真正的问题和答案
列出错误答案=新数组列表(3);
列表allAnswers=新阵列列表(4);
//循环3次,获得3个随机错误答案
对于(inti=0;i但首先我需要将文本与标志名进行比较,标志名是fn-if(text.equals(fn))哇,希伯来语注释。您的IDE不受RTL的影响吗?
onCreate() {
...
btnHint.setOnClickListener(hintOnClickListener);
...
Flag f = db.getFlag(randomNum); // This is the real question & answer
List<String> wrongAnswers = new ArrayList<String>(3);
List<String> allAnswers = new ArrayList<String>(4);
// Loop 3 times for 3 random wrong answers
for (int i=0; i<=3; i++) {
randNum = r.nextInt(200);
String randWrongAnswer = db.getFlag(randNum).getName().toString();
if (! wrongAnswers.contains(randWrongAnswer)) {
wrongAnswers.add(randWrongAnswer);
}
}
allAnswers.add(f.getName().toString());
allAnswers.addAll(wrongAnswers);
Collection.shuffle(allAnswers);
...
}
private OnClickListener hintOnClickListener = new OnClickListener() {
@Override
public void onClick(View v) {
G.numOfGuesses--;
// Since you shuffled the 'allAnswers' before displaying to the screen,
// we can just pick the first 2 answers from wrongAnswers list
// and it will appear to be random to the user.
for (int i=0; i < buttons.length; i++) {
String buttonText = buttons[i].getText().toString();
if (buttonText.equals(wrongAnswers.get(0))
|| buttonText.equals(wrongAnswers.get(1))) {
buttons[i].setVisibility(View.INVISIBLE);
}
}
}
};