Java 在ServletRequest到达Servlet/Filter后从中删除查询字符串
现在假设我发射一些URL,比如说Java 在ServletRequest到达Servlet/Filter后从中删除查询字符串,java,servlets,filter,query-string,Java,Servlets,Filter,Query String,现在假设我发射一些URL,比如说 http://shoaib:8080/userAuthentication?authenticate=false 现在当它到达过滤器的doFilter方法时 public void doFilter(request,response,filterChain){ boolean authenticate=request.getParameter("authenticate"); . . //some logic . .
http://shoaib:8080/userAuthentication?authenticate=false
现在当它到达过滤器的doFilter方法时
public void doFilter(request,response,filterChain){
boolean authenticate=request.getParameter("authenticate");
.
. //some logic
.
.
filterChain.doFilter(request,response); //this request should not have query String.
}
将传递给
filterChain的doFilter()
的请求不应具有queryString。如何实现这一点?我正在考虑覆盖过滤方法:
@Override
public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain)
throws ServletException, IOException {
HttpServletRequest request = (HttpServletRequest) req;
String requestURI = request.getRequestURI();
if (requestURI.startsWith(YOUR_CHECK_PATH)) {
String url = ((HttpServletRequest)request).getRequestURL().toString();
String queryString = ((HttpServletRequest)request).getQueryString();
req.getRequestDispatcher(url).forward(req, res);
} else {
chain.doFilter(req, res);
}
}
我尝试了很多,但最后我使用window.location对象更改了客户端的url 上一条路径:
http://shoaib:8080/userAuthentication?authenticate=false
客户端代码
window.location.pathname="userAuthentication";
这删除了以前的查询字符串
当前URL
http://shoaib:8080/userAuthentication
但是请求是否仍然具有查询字符串?因此,现在,如果下次调用request.getQueryString(),它应该为null。我想这不是一个答案,对此我不确定。但这行得通吗?Map params=request.getParameterMap();参数删除(“要删除的参数”)`我认为它不会像HTTP Status 500那样工作-不允许修改锁定的ParameterMap