java中的ROT-13函数?

java中的ROT-13函数?,java,rot13,Java,Rot13,作为标准Java库的一部分,是否已经有了rot13()和unrot13()实现?还是我必须自己写“重新发明轮子” 它可能看起来像这样: int rot13 ( int c ) { if ( (c >= 'A') && (c <= 'Z') ) c=(((c-'A')+13)%26)+'A'; if ( (c >= 'a') && (c <= 'z') ) c=(((c-'a')+13)%26)+'a';

作为标准Java库的一部分,是否已经有了
rot13()
unrot13()
实现?还是我必须自己写“重新发明轮子”

它可能看起来像这样:

int rot13 ( int c ) { 
  if ( (c >= 'A') && (c <= 'Z') ) 
    c=(((c-'A')+13)%26)+'A';

  if ( (c >= 'a') && (c <= 'z') )
    c=(((c-'a')+13)%26)+'a';

  return c; 
}
introt13(intc){

如果((c>='A')&&(c='A')&&(c我不认为默认情况下它是Java的一部分,但下面是一个如何实现它的示例

public class Rot13 { 

    public static void main(String[] args) {
        String s = args[0];
        for (int i = 0; i < s.length(); i++) {
            char c = s.charAt(i);
            if       (c >= 'a' && c <= 'm') c += 13;
            else if  (c >= 'A' && c <= 'M') c += 13;
            else if  (c >= 'n' && c <= 'z') c -= 13;
            else if  (c >= 'N' && c <= 'Z') c -= 13;
            System.out.print(c);
        }
        System.out.println();
    }

}
公共类Rot13{
公共静态void main(字符串[]args){
字符串s=args[0];
对于(int i=0;i如果(c>='a'&&c='a'&&c='n'&&c='n'&&c也可以贡献我的功能来节省其他开发人员宝贵的时间

public static String rot13(String input) {
   StringBuilder sb = new StringBuilder();
   for (int i = 0; i < input.length(); i++) {
       char c = input.charAt(i);
       if       (c >= 'a' && c <= 'm') c += 13;
       else if  (c >= 'A' && c <= 'M') c += 13;
       else if  (c >= 'n' && c <= 'z') c -= 13;
       else if  (c >= 'N' && c <= 'Z') c -= 13;
       sb.append(c);
   }
   return sb.toString();
}
公共静态字符串rot13(字符串输入){
StringBuilder sb=新的StringBuilder();
对于(int i=0;i如果(c>='a'&&c='a'&&c='n'&&c='n'&&c,这里是我在字符串中移位字符的解决方案

public static void main(String[] args) {
    String input = "melike";
    int shiftCount = 13;
    char[] encryptedChars = encryptedChars(shiftCount);
    System.out.println(new String(encryptedChars));
    char[] decryptedChars = decryptedChars(shiftCount);
    System.out.println(new String(decryptedChars));
    String encrypted = encrypt(input, shiftCount);
    System.out.println(encrypted);
    String decrypted = decrypt(encrypted, shiftCount);
    System.out.println(decrypted);
    System.out.println(input.equals(decrypted));
}

private static String decrypt(String input, int shiftCount) {
    char[] decryptedChars = decryptedChars(shiftCount);
    char[] chars = input.toCharArray();
    char[] newChars = new char[chars.length];
    for (int i = 0; i < chars.length; i++) {
        int diff = chars[i] - 'a';
        newChars[i] = decryptedChars[diff];
    }
    return new String(newChars);
}

private static String encrypt(String input, int shiftCount) {
    char[] encryptedChars = encryptedChars(shiftCount);
    char[] chars = input.toCharArray();
    char[] newChars = new char[chars.length];
    for (int i = 0; i < chars.length; i++) {
        int diff = chars[i] - 'a';
        newChars[i] = encryptedChars[diff];
    }
    return new String(newChars);
}

private static char[] encryptedChars(int shiftCount) {
    char[] newChars = new char[26];
    for (int i = 0; i < 26; i++) {
        newChars[i] = (char) ('a' + (i + shiftCount) % 26);
    }
    return newChars;
}

private static char[] decryptedChars(int shiftCount) {
    char[] newChars = new char[26];
    for (int i = 0; i < 26; i++) {
        newChars[i] = (char) ('a' + (i - shiftCount + 26) % 26);
    }
    return newChars;
}
publicstaticvoidmain(字符串[]args){
字符串输入=“melike”;
int shiftCount=13;
char[]encryptedChars=encryptedChars(移位计数);
System.out.println(新字符串(encryptedChars));
char[]decryptedChars=decryptedChars(shiftCount);
System.out.println(新字符串(decryptedChars));
字符串加密=加密(输入,移位计数);
System.out.println(加密);
字符串解密=解密(加密,移位计数);
System.out.println(已解密);
System.out.println(input.equals(解密));
}
私有静态字符串解密(字符串输入,int shiftCount){
char[]decryptedChars=decryptedChars(shiftCount);
char[]chars=input.toCharArray();
char[]newChars=新字符[chars.length];
for(int i=0;i
@BNL我个人更喜欢rot104。需要专用协处理器though@BNL哈哈,谁说这是出于安全目的?顺便说一句,rot13是它自己的逆函数,所以你实际上不需要“unrot13”方法。谢谢你花时间把它放到一个方法中。你也复制了吗?