Java 为什么不';线程池中的所有线程是否都在处理我的排队任务?
我编写了一个简单的Java程序来帮助使用线程和线程池来完成某些任务。在我的程序中,有类Java 为什么不';线程池中的所有线程是否都在处理我的排队任务?,java,multithreading,synchronization,threadpool,Java,Multithreading,Synchronization,Threadpool,我编写了一个简单的Java程序来帮助使用线程和线程池来完成某些任务。在我的程序中,有类TheObject的对象必须对它们进行某种处理(在这种情况下,只是一个睡眠延迟并打印出它们的字段) object对象被放置在队列中,从队列中WorkerThreads绘制并处理它们 我创建了一个Manager类来初始化TheObjectss和WorkerThreads。当我运行它时,我得到了奇怪的输出;不是线程关闭工作,而是一个线程处理所有事情!为什么会这样?如何让线程共享工作负载 这是输出: --------
TheObject
的对象必须对它们进行某种处理(在这种情况下,只是一个睡眠延迟并打印出它们的字段)
object
对象被放置在队列中,从队列中WorkerThread
s绘制并处理它们
我创建了一个Manager
类来初始化TheObjects
s和WorkerThread
s。当我运行它时,我得到了奇怪的输出;不是线程关闭工作,而是一个线程处理所有事情!为什么会这样?如何让线程共享工作负载
这是输出:
--------------------------------------------
alfred a 0
Thread-0
--------------------------------------------
bob b 1
Thread-0
--------------------------------------------
carl c 2
Thread-0
--------------------------------------------
dave d 3
Thread-0
--------------------------------------------
earl e 4
Thread-0
--------------------------------------------
fred f 5
Thread-0
--------------------------------------------
greg g 6
Thread-0
--------------------------------------------
harry h 7
Thread-0
--------------------------------------------
izzie i 8
Thread-0
--------------------------------------------
jim j 9
Thread-0
--------------------------------------------
kyle k 0
Thread-0
--------------------------------------------
Larry L 1
Thread-1
--------------------------------------------
Michael M 2
Thread-1
--------------------------------------------
Ned N 3
Thread-0
--------------------------------------------
Olaf O 4
Thread-0
--------------------------------------------
Peter P 5
Thread-0
--------------------------------------------
Quincy Q 6
Thread-0
--------------------------------------------
Raphael R 7
Thread-0
--------------------------------------------
Sam S 8
Thread-0
--------------------------------------------
Trixie T 9
Thread-0
守则: 课程:
- 经理
- 对象
- 对象队列
- 工作线程
public class Manager {
public static void main(String[] args) throws InterruptedException {
TheObjectQueue queue = new TheObjectQueue();
//Create Objects
int numberOfInitialObjects = 10;
String[] arrayOfNames = {"alfred", "bob", "carl", "dave", "earl", "fred", "greg", "harry", "izzie", "jim"};
//char[] arrayOfChars = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j'};
//int[] arrayOfNums = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
for (int i = 0; i < numberOfInitialObjects; i++){
TheObject anObject = new TheObject(arrayOfNames[i], arrayOfNames[i].charAt(0), i);
queue.addToQueue(anObject);
}
int numberOfThreads = 2;
for (int i = 0; i < numberOfThreads; i++){
WorkerThread workerThread = new WorkerThread(queue);
workerThread.start();
}
try {
Thread.sleep(5000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String[] arrayOfNames2 = {"kyle", "Larry", "Michael", "Ned", "Olaf", "Peter", "Quincy", "Raphael", "Sam", "Trixie"};
for (int i = 0; i < numberOfInitialObjects; i++){
TheObject anObject = new TheObject(arrayOfNames2[i], arrayOfNames2[i].charAt(0), i);
queue.addToQueue(anObject);
}
}
}
对象队列
import java.util.LinkedList;
public class TheObjectQueue {
private LinkedList<TheObject> objectQueue = null;
public TheObjectQueue(){
objectQueue = new LinkedList<TheObject>();
}
public LinkedList<TheObject> getQueue(){
return objectQueue;
}
public void addToQueue(TheObject obj){
synchronized (this) {
objectQueue.addFirst(obj);
this.notify();
}
}
public TheObject removeFromQueue(){
synchronized (this) {
TheObject obj = objectQueue.removeLast();
return obj;
}
}
public int getSize(){
return objectQueue.size();
}
public boolean isEmpty(){
return objectQueue.isEmpty();
}
}
WorkerThread.run中(共享)队列上的同步只允许单个线程一次处理一个任务-其效果实际上是一个工作线程池!在这种情况下,线程0在获得锁的大部分时间“获胜”;同步锁获取是一种有效的方法 一个简单的修复方法是使用所需的线程安全构造从队列中获取任务,然后在同步部分之外处理任务。这允许工作人员同时处理假定为独立的任务
// e.g.
@Override
public void run() {
while(true){
TheObject objToDealWith;
synchronized (queue) {
// Only synchronized on queue when fetching task
objToDealWith = getTask(queue);
}
// Process task; independent of queue
process(objToDealWith);
}
}
由于其中一个线程将忙于处理任务,而另一个线程正在(或已经)获取队列上的锁,因此工作分配将“公平”。为什么如此困难?
只需使用java提供的
如果你是手写的,你就做错了
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Sample {
public static void main(String[] args) {
// configure here how many threads and other properties, the queue here is actually build in.
ExecutorService executor = Executors.newCachedThreadPool();
String[] arrayOfNames = { "alfred", "bob", "carl", "dave", "earl",
"fred", "greg", "harry", "izzie", "jim" };
for (int i = 0; i < arrayOfNames.length; i++) {
TheObject anObject = new TheObject(arrayOfNames[i], arrayOfNames[i].charAt(0), i);
MyRunnable runnalbe = new MyRunnable(anObject);
executor.execute(runnalbe);
}
executor.shutdown()
}
static class MyRunnable implements Runnable {
final TheObject anObject;
MyRunnable(TheObject theObject) {
this.anObject = theObject;
}
@Override
public void run() {
//TODO do work with anObject
}
}
static class TheObject {
private String someName;
private char someChar;
private int someNum;
public TheObject(String someName, char someChar, int someNum) {
this.someName = someName;
this.someChar = someChar;
this.someNum = someNum;
}
public String getSomeName() {
return someName;
}
public char getSomeChar() {
return someChar;
}
public int getSomeNum() {
return someNum;
}
}
}
导入java.util.concurrent.ExecutorService;
导入java.util.concurrent.Executors;
公共类样本{
公共静态void main(字符串[]args){
//在这里配置多少线程和其他属性,这里的队列实际上是内置的。
ExecutorService executor=Executors.newCachedThreadPool();
String[]arrayOfNames={“alfred”、“bob”、“carl”、“dave”、“earl”,
“弗雷德”、“格雷格”、“哈利”、“伊兹”、“吉姆”};
for(int i=0;i
为什么不使用ExecutorService?@Jarrod我看不出这是一个复制品。即使存在不同的工具来实现这一点,问题并不在于它们的使用。我正在重新打开。此行为的一个可能原因是isEmpty()
未同步,因此除thread-0
之外的所有其他工作线程始终将队列视为空。哦,不,你调用了isEmpty
在队列上保持锁定,所以isEmpty()
应该按预期工作。你回答的是问题的哪一部分?最多,这应该是一个注释。全部。重新设计队列?不可能。重塑ExecutorService/ThreadPool?不,重新发明轮子?不,改造一个螺纹工厂?不,所以我的答案是:使用java提供的工具。=>如果您使用这些类,就不会有问题。然后向我们展示如何使用ExecutorService
解决OP的问题。仅链接的答案是。@Zarathustra根据代码以及Includeuser2864740
的答案,如果使用ExecutorService
,是否缺少任何内容?
// e.g.
@Override
public void run() {
while(true){
TheObject objToDealWith;
synchronized (queue) {
// Only synchronized on queue when fetching task
objToDealWith = getTask(queue);
}
// Process task; independent of queue
process(objToDealWith);
}
}
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Sample {
public static void main(String[] args) {
// configure here how many threads and other properties, the queue here is actually build in.
ExecutorService executor = Executors.newCachedThreadPool();
String[] arrayOfNames = { "alfred", "bob", "carl", "dave", "earl",
"fred", "greg", "harry", "izzie", "jim" };
for (int i = 0; i < arrayOfNames.length; i++) {
TheObject anObject = new TheObject(arrayOfNames[i], arrayOfNames[i].charAt(0), i);
MyRunnable runnalbe = new MyRunnable(anObject);
executor.execute(runnalbe);
}
executor.shutdown()
}
static class MyRunnable implements Runnable {
final TheObject anObject;
MyRunnable(TheObject theObject) {
this.anObject = theObject;
}
@Override
public void run() {
//TODO do work with anObject
}
}
static class TheObject {
private String someName;
private char someChar;
private int someNum;
public TheObject(String someName, char someChar, int someNum) {
this.someName = someName;
this.someChar = someChar;
this.someNum = someNum;
}
public String getSomeName() {
return someName;
}
public char getSomeChar() {
return someChar;
}
public int getSomeNum() {
return someNum;
}
}
}