Java 原则上存储多个值

我用这个原理来存储当前的用户id

存储

   val principalExtractor: (MutableMap<String, Any?>) -> Any? = { params ->
        val session = params.get("session") as MutableMap<String, Any?>
        val user = session.get("user") as MutableMap<String, Any?>
        user.get("email")
    }

问题： 我面临的情况是，我需要从会议中获得更多细节，例如：-companyId-

我想在principle上存储一个用户对象，而不仅仅是一个字符串，但是principle.name默认返回字符串

问题：

---

我如何根据原则（子类？）存储对象，或者有更好的方法吗？

通过使用身份验证解决了这个问题

拖拉机

val principalExtractor: (MutableMap<String, Any?>) -> Any? = { params ->
        val session = params.get("session") as MutableMap<String, Any?>
        val user = session.get("user") as MutableMap<String, Any?>
        val mapper = ObjectMapper()
        mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)
        val userDetails = mapper.convertValue(user, UserDetails::class.java)
        userDetails
    }

val principalExtractor: (MutableMap<String, Any?>) -> Any? = { params ->
        val session = params.get("session") as MutableMap<String, Any?>
        val user = session.get("user") as MutableMap<String, Any?>
        val mapper = ObjectMapper()
        mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)
        val userDetails = mapper.convertValue(user, UserDetails::class.java)
        userDetails
    }

@GetMapping("{userId}/activationWidgetUrl")
    fun getActivationWidgetUrl(authentication: Authentication, @PathVariable userId: String): ActivationWidgetResponse? {

       (authentication.principal as UserDetails).let { userDetails ->
            let id = userDetails.id
        }

}