Java Hibernate条件查询不考虑多个限制
我正在尝试使用条件查询2个表。方法如下:Java Hibernate条件查询不考虑多个限制,java,hibernate,criteria,Java,Hibernate,Criteria,我正在尝试使用条件查询2个表。方法如下: public UserEntity getUserOverView(long userId, String receiptMonth) { Session session = HibernateUtil.getSessionFactory().openSession(); UserEntity user = new UserEntity(); try { session.beginTransaction();
public UserEntity getUserOverView(long userId, String receiptMonth) {
Session session = HibernateUtil.getSessionFactory().openSession();
UserEntity user = new UserEntity();
try {
session.beginTransaction();
Criteria criteria = session.createCriteria(UserEntity.class, "user")
.createAlias("user.receiptEntitySet", "receipt")
.add(Restrictions.eq("receipt.dateCreated", receiptMonth))
.add(Restrictions.eq("user.userId", userId));
user = (UserEntity) criteria.uniqueResult();
} catch (Exception ex) {
System.out.print(ex.getMessage());
} finally {
session.getTransaction().commit();
session.close();
}
return user;
}
上面提到的是用户ID,但是,我想在另一个表中的“receiptMonth”上进行筛选。它似乎完全忽略了“receiptMonth”限制
用户实体:
package za.co.skizzel.infrastructure.entities;
import javax.persistence.*;
import java.util.Set;
@Entity
@Table(name="user")
public class UserEntity {
@Id
@GeneratedValue
@Column(name="userId", unique = true, nullable = false, updatable = false )
private Long userId;
@Column(name="email")
private String email;
@Column(name="password")
private String password;
@Column(name="name")
private String name;
@OneToMany(fetch = FetchType.EAGER, mappedBy = "userEntity" , cascade = { CascadeType.ALL } )
private Set<ReceiptEntity> receiptEntitySet;
@OneToMany(fetch = FetchType.EAGER, mappedBy = "userEntity" , cascade = { CascadeType.ALL } )
private Set<CategoryEntity> categoryEntitySet;
public Set<CategoryEntity> getCategoryEntitySet() {
return categoryEntitySet;
}
public void setCategoryEntitySet(Set<CategoryEntity> categoryEntitySet) {
this.categoryEntitySet = categoryEntitySet;
}
public Long getUserId() {
return userId;
}
public void setUserId(Long userId) {
this.userId = userId;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Set<ReceiptEntity> getReceiptEntitySet() {
return receiptEntitySet;
}
public void setReceiptEntitySet(Set<ReceiptEntity> receiptEntitySet) {
this.receiptEntitySet = receiptEntitySet;
}
public UserEntity(){};
public UserEntity(long userId){
this.userId = userId;
};
}
这行吗
Criteria criteria = session.createCriteria(UserEntity.class)
.createAlias("receiptEntitySet", "receipt")
.add(Restrictions.eq("receipt.dateCreated", receiptMonth))
.add(Restrictions.eq("userId", userId));
编辑
此查询将返回与条件匹配的整体UserEntity
。例如,如果您在receiptEntitySet
中有一个userEntity
和两个ReceiptEntity
s,其中一个具有dateCreated=receiptMonth
,那么您将在receiptEntitySet
中获得两个接收实体的userEntity
。该userEntity
将是附加的实体(绑定到Hibernate会话),并将表示该对象的数据库状态,其中包括两个接收实体
您的选项取决于您的用例,但通常您可以将用户和收据保存在单独的字段中,您可以通过循环填写收据
List<ReceiptEntity> filteredReceipts = new ArrayList<ReceiptEntity>();
for (ReceiptEntity receipt : user.getReceiptEntitySet()) {
if (receipt.getDateCreated().equals(receiptMonth) {
filteredReceipts.add(receipt);
}
}
希望这有帮助。您需要在这里执行一些高级SQL。SQL不知道如何将“2014年1月”与日期字段进行比较。此外,您不能只比较这两个日期,因为月初的日期不等于月底的日期(或日、小时、分钟……等等),因此您需要从目标字段中提取月份和年份进行筛选,并将每个月份和年份与您要筛选的月份和年份进行比较 我认为,这方面的东西可能会对你有所帮助:
public void test(){
SimpleDateFormat f = new SimpleDateFormat("MMM yyyy");
Date d = null;
String userId = "userId";
try {
d = f.parse("January 2014");
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
if(d!= null){
System.out.println("Date is: "+d.toString());
Criteria c = this.getSession().createCriteria(UserEntity.class)
.add(Restrictions.sqlRestriction("extract('month' from cast('"+d.toString()+"' as timestamp)) = extract('month' from reciept.dateCreated) and extract('year' from cast('"+d.toString()+"' as timestamp)) = extract('year' from reciept.dateCreated)"))
.add(Restrictions.eq("userId", userId));
}
}
希望这能有所帮助。您希望结果如何?如果您希望将其
receiptEntitySet
过滤为只包含给定receiptMonth
的UserEntity
,那么您的期望是错误的。如果此查询至少包含一个ReceiptEntity
和给定的dateCreated
,则应返回具有给定id的UserEntity
及其所有字段。我希望我的查询仅返回基于给定userId和receiptMonth的结果。查看我的编辑。根据您的条件,您的查询将返回整个UserEntity
。如果您有userEntity
和userId=1
以及receiptEntitySet
中的两个ReceiptEntity
,其中一个具有creationDate=receiptMonth
,则您将获得两个接收实体的整个userEntity
。如果您只需要一个与receiptMonth
匹配的收据实体,您将需要另一个/不同的查询。您能提供一个例子吗?我已经编辑了我的答案,并添加了注释中提到的内容。我没有做日期比较,只是尝试查询使用该参数创建的所有记录(2014年1月)。
List<ReceiptEntity> filteredReceipts = new ArrayList<ReceiptEntity>();
for (ReceiptEntity receipt : user.getReceiptEntitySet()) {
if (receipt.getDateCreated().equals(receiptMonth) {
filteredReceipts.add(receipt);
}
}
Criteria criteria = session.createCriteria(ReceiptEntity.class)
.createAlias("user", "user")
.add(Restrictions.eq("dateCreated", receiptMonth))
.add(Restrictions.eq("user.userId", userId));
public void test(){
SimpleDateFormat f = new SimpleDateFormat("MMM yyyy");
Date d = null;
String userId = "userId";
try {
d = f.parse("January 2014");
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
if(d!= null){
System.out.println("Date is: "+d.toString());
Criteria c = this.getSession().createCriteria(UserEntity.class)
.add(Restrictions.sqlRestriction("extract('month' from cast('"+d.toString()+"' as timestamp)) = extract('month' from reciept.dateCreated) and extract('year' from cast('"+d.toString()+"' as timestamp)) = extract('year' from reciept.dateCreated)"))
.add(Restrictions.eq("userId", userId));
}
}