Java 无法将字符串转换为整数。有时会收到NumberFormatException
我正在尝试从facebook帐户获取按摩次数、通知次数和好友请求次数。从facebook获取字符串数据后,我使用integer.parseInt(string)方法将其转换为integer。根据我的代码逻辑,我将从facebook获取的数据放入error、error1和error2中,当它们是字符串时,将它们转换为integer后,我将它们放入actualfriend、actualmassage和actualnotification中。最后,我将实际数据与一些预期数据进行比较 问题是我得到了正确的按摩计数结果,但对于朋友请求和通知,我在error1和error2中得到了正确的数据,但一旦我将它们从字符串转换成整数,我得到了actualfriend=0和actualnotification=0Java 无法将字符串转换为整数。有时会收到NumberFormatException,java,string,exception,if-statement,numberformatexception,Java,String,Exception,If Statement,Numberformatexception,我正在尝试从facebook帐户获取按摩次数、通知次数和好友请求次数。从facebook获取字符串数据后,我使用integer.parseInt(string)方法将其转换为integer。根据我的代码逻辑,我将从facebook获取的数据放入error、error1和error2中,当它们是字符串时,将它们转换为integer后,我将它们放入actualfriend、actualmassage和actualnotification中。最后,我将实际数据与一些预期数据进行比较 问题是我得到了正确
public void operation() throws InterruptedException, AWTException ,StaleElementReferenceException,NoSuchElementException,NumberFormatException {
int i=1;
int j=1;
while(i==1){
String error = "1";
String error1= "1";
String error2= "1";
System.out.println(error);
if((error.length() != 0) && (error1.length() != 0) && (error2.length() != 0)){
try{
actualmassage = Integer.parseInt(error);
}catch (NumberFormatException e) {
error="5";
try{
actualnotification=Integer.parseInt(error1);
}catch(NumberFormatException ee){
error1="5";
try{
actualfriend=Integer.parseInt(error2);
}catch(NumberFormatException eee){
error2="5";
}//catch3
}//catch2
}//catch3
}//if for massage
else if((error.length() !=0) && (error1.length() !=0) && (error2.length() !=0)){
actualmassage = Integer.parseInt(error);
actualnotification = Integer.parseInt(error1);
actualfriend = Integer.parseInt(error2);
}//else if
else{
}//else
int expectedmassage =1;
int expectednotification=0;
int expectedfriend=0;
if(expectedmassage == actualmassage ){
Thread.sleep(4000);
System.out.println("Readable Massage = "+error +" actualmassage = "+actualmassage);
}else{
System.outprintln("Does't Match");
i++;
}//else
if(expectednotification == actualnotification){
Thread.sleep(4000);
System.out.println("Total Notification = "+error1 +" actualnotification = "+actualnotification);
}else{
System.outprintln("Does't Match");
i++;
}//else
if(expectedfriend == actualfriend ){
Thread.sleep(4000);
System.out.println("Total FriendRequest = "+error2 +" actualfriend = "+actualfriend);
}else{
System.outprintln("Does't Match");
i++;
}//else
//Counting number of runs
System.out.println("Number of run = " + j);
j++;
}//while
System.out.println("Stop");
i=(i+2);
}//operation
public static void main(String[] args) throws StaleElementReferenceException, InterruptedException, AWTException,NoSuchElementException,NumberFormatException{
fb c = new fb();
}//main
}//calss
Output for this-
1
Readable Massage = 1 actualmassage = 1
Total Notification = 1 actualnotification = 0
Total FriendRequest = 1 actualfriend = 0
Number of run = 1
1
Readable Massage = 1 actualmassage = 1
Total Notification = 1 actualnotification = 0
Total FriendRequest = 1 actualfriend = 0
Number of run = 2
如您所见,我得到了-Readable message=1(从错误变量获取)actualmassage=1(从字符串转换为整数后从actualmassage获取)。Total Notification=1(从error1变量获取)actualnotification=0(从字符串转换为整数后从actualmassage获取),这是错误的。Total FriendRequest=1(从error2变量获取)actualfriend=0(从字符串转换为整数后从actualfriend获取),这是错误的
将代码从-
int expectedmassage =1;
int expectednotification=0;
int expectedfriend=0;
if(expectedmassage == actualmassage ){
Thread.sleep(4000);
System.out.println("Readable Massage = "+error +" actualmassage = "+actualmassage);
}else{
System.out.print("Does't match");
i++;
}//else
if(expectednotification == Integer.parseInt(error1)){
Thread.sleep(4000);
System.out.println("Total Notification = "+error1 +" actualnotification = "+actualnotification);
}else{
System.out.print("Does't match");
i++;
}//else
if(expectedfriend == Integer.parseInt(error2)){
Thread.sleep(4000);
System.out.println("Total FriendRequest = "+error2 +" actualfriend = "+actualfriend);
}else{
System.out.print("Does't match");
i++;
}//else
但是做了这件事之后,我得到了-
1
java.lang.NumberFormatException: For input string: ""
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at com.selenium.fb.main1(fb.java:103)
at com.selenium.fb.main(fb.java:123)
第一个if(error.length()!=0)&&&&(error1.length()!=0)&&(error2.length()!=0)无法为actualnotification和actualfriend赋值,因为它们没有到达。请使用以下代码更改代码。我为每一个创建了单独的if块,它成功了
try{
actualmassage = Integer.parseInt(error);
}catch (NumberFormatException e) {
error="0";
}//catch1
}//if1
if((error1.length() != 0)){
try{
actualnotification=Integer.parseInt(error1);
}catch(NumberFormatException ee){
error1="0";
}//catch2
}//if2
if((error2.length() != 0)){
try{
actualfriend=Integer.parseInt(error2);
}catch(NumberFormatException eee){
error2="0";
}//catch3
}//if3
您的问题看起来好像是由某个文本生成器创建的。你能做的最起码的事情就是检查你的问题,问问自己它是否可读,以及你能做些什么来改进它。提示:从清楚地解释问题开始。删除所有不必要的代码-使用可以显示如何重现问题的最小代码示例等@alfasin I更改了问题Sir的格式第
fb.java:103行中发生了什么?看起来您正在尝试解析一个空字符串。