Java 如何获取一行文本并删除括号中的所有注释、空行、额外空格和信息？

这个项目要求我读取一个正在处理的文件，去掉括号中的所有注释、空行、额外空格和信息，然后将其打印到output.txt中。我在处理数据和删除括号中的所有注释、空行、额外空格和信息时遇到了问题

这是我的密码：

import java.util.Scanner;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintWriter;

/*
 * @author wrigh4d
 * Date: 11/7/19
 * Description:  Takes instruction from SumN and then prints it into output.txt 
 */

public class InstructionExtractor {

    public static void main(String[] args) throws FileNotFoundException {
        //Sets up Scanner/Print Writer and declares variable
        File myFile = new File("sumN.txt");
        Scanner sc = new Scanner(myFile);

        File outputFile = new File("output.txt");
        PrintWriter pw = new PrintWriter(outputFile);

        String currentLine = "";

        //Sets up while loop to read in each line
        while(sc.hasNextLine()) {
            currentLine = sc.nextLine();    //Sets each line to currentLine
            currentLine = processLine(currentLine); //Takes currentLine down to processLine
            if(currentLine != "") { //if there is something inside of current Line it appends it to printwriter
                pw.append(currentLine + "\n");
            }

        }

        pw.flush(); //prints onto output.txt

    }

    public static String processLine(String currentLine) {
        //Gets rid of whitespace inside of currentLine
        String a = currentLine.replaceAll("\\s+","");
        System.out.println(a);

        return a;

    }

}

这里是SumN：

// Adds 1+...+100.
//initialize variable i and sum
@i // i refers to some mem. location.
M=1 // i=1
@sum // sum refers to some mem. location.
M=0 // sum=0

//the loop to sum
(LOOP)  //the LOOP label
@i
D=M // D=i
@100
D=D-A // D=i-100
@END
D;JGT // If (i-100)>0 goto END
@i
D=M // D=i
@sum
M=D+M // sum=sum+i
@i
M=M+1 // i=i+1
@LOOP
0;JMP // Goto LOOP

//Terminate the program
(END)
@END
0;JMP // Infinite loop

您可以使用a来匹配要取出的物品：

public static String processLine(String currentLine) {
    // Gets rid of whitespace inside of currentLine
    String a = currentLine.replaceAll("//.+|\\s|\\(.+", "");
    System.out.println(a);

    return a;
}

还可以使用isEmpty（）函数而不是！=“”：

---

您基本上需要一个解析器。您可能可以使用

String.split（）

和一些逻辑。您可以避免代码中的注释重复类似

Object a=new Object（）；//创建名为a的新对象

那么，您遇到的具体问题是什么？您是否考虑过按字符操作而不是按令牌/行操作，如图所示？

// Sets up while loop to read in each line
while (sc.hasNextLine()) {
    currentLine = sc.nextLine(); // Sets each line to currentLine
    currentLine = processLine(currentLine); // Takes currentLine down to processLine
        if (!currentLine.isEmpty()) { // if there is something inside of current Line it appends it to printwriter
            pw.append(currentLine + "\n");
    }
}