Java Android上的startActivity（intent）不工作

因此，我试图通过序列化传递一些信息，但由于某些原因，它不起作用，我编写了两个

Log.e（）

用于测试，根据

LogCat

它说它没有通过

startactivity（intent）

这是我的密码

public class MainActivity extends Activity {

    FileManager file = new FileManager();
    FileInputStream fileInput; 
    FileOutputStream fileOutput; 
    SortedArrayList<Contact> contactList = new SortedArrayList<Contact>();
    ArrayList<Contact> theList =new ArrayList<Contact>();

    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        try {
            fileInput = openFileInput("contacts.txt");
            Log.e("FILE INPUT","FOUND!!");
            contactList = file.read(fileInput,getApplicationContext());
            Log.e("_____",contactList.toString());
        } 
        catch (Exception e) {
            Log.e("Error","ERROR CREATING FILE");
        }

        if(contactList.size() != 0){
            ListView lv =(ListView)findViewById(R.id.contactList);
            for(int i=0;i<contactList.size();i++){
                theList.add(contactList.get(i));
            }
            ArrayAdapter<Contact> adapter = new MyListAdapter();
            lv.setAdapter(adapter);
            clickOnContact();
        }

        // Create The Adapter with passing ArrayList as 3rd parameter
        //OrderAdapter arrayAdapter =  new OrderAdapter(this, R.layout.list_view, contactListNameView, contactListLastNameView, contactListCellphoneView);    
        //Set The Adapter
        //lv.setAdapter(arrayAdapter); 

    }

    private void clickOnContact() {
        ListView list = (ListView) findViewById(R.id.contactList);
        list.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View viewClicked, int pos,
                    long id) {  
            Contact Contact = theList.get(pos);
            Log.e("contact: ",Contact.getFirstName());
            try{    
                Intent intent = new Intent(MainActivity.this, ShowContactActivity.class);
                Log.e("pass ","1");
                intent.putExtra("Contact",Contact);
                Log.e("pass ","2");
                startActivity(intent);
            }
            catch (Exception e){
                Log.e("didnt","pass catch");
            }   
        }       
    }); 
}

private class MyListAdapter extends ArrayAdapter<Contact> {

    public MyListAdapter() {
        super(MainActivity.this, R.layout.list_view, theList);
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View itemView = convertView;    
        if(itemView == null){
            itemView = getLayoutInflater().inflate(R.layout.list_view, parent, false);
        }   
        Contact contact = theList.get(position);    
        //Fill First Name
        TextView name = (TextView) itemView.findViewById(R.id.contactName);
        name.setText(contact.getFirstName());   
        //Fill Last Name
        TextView lastname = (TextView) itemView.findViewById(R.id.contactLastName);
        lastname.setText(contact.getLastName());
        return itemView;
    }

}

像

Contact contact = theList.get(pos);  //contact is the object of the class (small c)

---

查看

Contact Contact=list.get（pos）。出什么事了？为对象使用不同的名称（至少是小写字母）。只是这样做了，不会出现相同的错误…@user2896762也在此处更改它。。！！意向。额外（“联系”，联系）；只是修复了它，我不知道ArrayList没有实现Serializable，所以我使用了我构建的数据结构，它工作了@用户2896762：好的。如果我的回答对你有帮助，请接受
Contact contact = theList.get(pos);  //contact is the object of the class (small c)