Java 如何在android中播放来自服务器的音频
我通过以下代码将所有音频文件列表从服务器转到列表视图Java 如何在android中播放来自服务器的音频,java,android,audio,android-listview,classcastexception,Java,Android,Audio,Android Listview,Classcastexception,我通过以下代码将所有音频文件列表从服务器转到列表视图 public class ServerFileList extends Activity { URL urlAudio; ListView mListView; ProgressDialog pDialog; private MediaPlayer mp = new MediaPlayer(); private List<String> myList = new ArrayList<
public class ServerFileList extends Activity {
URL urlAudio;
ListView mListView;
ProgressDialog pDialog;
private MediaPlayer mp = new MediaPlayer();
private List<String> myList = new ArrayList<String>();
@Override
protected void onCreate(Bundle savedInstanceState) {
this.requestWindowFeature(Window.FEATURE_NO_TITLE);
super.onCreate(savedInstanceState);
setContentView(R.layout.serverfilelist);
mListView = (ListView) findViewById(R.id.listAudio);
new getAudiofromServer().execute();
new downloadAudioFromServer().execute();
mListView.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
playSong(urlAudio + myList.get(position));
}
});
}
private void playSong(String songPath) {
try {
mp.reset();
mp.setDataSource(songPath);
mp.prepare();
mp.start();
} catch (IOException e) {
Log.v(getString(R.string.app_name), e.getMessage());
}
}
private class downloadAudioFromServer extends
AsyncTask<String, Integer, String> {
@Override
protected String doInBackground(String... url) {
int count;
try {
URL url1 = new URL("http://i-qualtech.com/Fidol/uploadAudio");
URLConnection conexion = url1.openConnection();
conexion.connect();
int lenghtOfFile = conexion.getContentLength();
InputStream input = new BufferedInputStream(url1.openStream());
OutputStream output = new FileOutputStream(
Environment.getExternalStorageDirectory() + "/Sounds/");
byte data[] = new byte[1024];
long total = 0;
while ((count = input.read(data)) != -1) {
total += count;
// publishing the progress....
publishProgress((int) (total * 100 / lenghtOfFile));
output.write(data, 0, count);
}
output.flush();
output.close();
input.close();
} catch (Exception e) {
}
return null;
}
}
class getAudiofromServer extends AsyncTask<String, String, String> {
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(ServerFileList.this);
pDialog.setMessage("Getting File list from server, Please wait...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(false);
pDialog.show();
}
@SuppressWarnings("unchecked")
@Override
protected String doInBackground(String... arg0) {
try {
urlAudio = new URL("http://i-qualtech.com/Fidol/uploadAudio");
} catch (MalformedURLException e) {
e.printStackTrace();
}
ApacheURLLister lister1 = new ApacheURLLister();
try {
myList = lister1.listAll(urlAudio);
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
protected void onPostExecute(String file_url) {
if (pDialog.isShowing()) {
pDialog.dismiss();
}
ArrayAdapter<String> adapter = new ArrayAdapter<String>(
ServerFileList.this, android.R.layout.simple_list_item_1,
myList);
adapter.notifyDataSetChanged();
mListView.setAdapter(adapter);
mListView.setChoiceMode(ListView.CHOICE_MODE_SINGLE);
mListView.setCacheColorHint(Color.TRANSPARENT);
}
}
}
为什么不先通过将URL对象转换为字符串来准备播放所需的正确URL 像这样的改变: 播放歌曲(urlAudio+myList.get(position))强> 到
播放歌曲(urlAudio.toString()+myList.get(position))我不知道这段代码是否对您有帮助 但是试试看: 在重新创建之前
Uri uri;
添加到您的代码中
mListView.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
//playSong(urlAudio + myList.get(position));
uri = Uri.parse(urlAudio);
playSong(urlAudio + myList.get(position));
}
});
我已经设法解决了这个问题,只是在我的mclicklistner中添加了下面的一段代码,它现在运行良好
String url = null;
Object o = myList.get(position);
url = o.toString().replace(" ", "%20").trim();
play = (PlaySongAsy) new PlaySongAsy(url).execute();
请将您要传递的url字符串发布到playSong()中,好吗?谢谢是的,您可以在上面检查mp3文件名。myList.get(position)在调用中返回的是什么:playSong(urlAudio+myList.get(position))?它将返回列表视图项的位置我知道它从技术上返回什么。我想知道你打电话时得到的价值是多少。您是否尝试过调试应用程序,在“播放歌曲”前停下来检查到底通过了什么?您正在连接两个字符串。一个显然是URL,它不能“按原样”添加到字符串中。需要使用toString方法将其转换为字符串。另一部分由列表返回。你能不能把这两件事分解一下,存储在局部变量中,调试一下,看看填充的值是什么,它们是否正确。谢谢但是urlAudio不是一个字符串,在调用时我不能在参数中传递URL。但是你不能从任何地方调用playSong方法。现在检查代码,如果你不需要playSong方法中的“songPath”,请将其从方法和callingOkay中删除,如果将songPath保留在方法中,那么我将得到与前面相同的错误。但若我删除路径,那个么我并没有得到错误,但我也不能播放歌曲。意味着它没有播放那个音频。还有一件事我得到了E/MediaPlayer(27461):错误(1,-2147483648)logcat中的这个错误。
private void playSong(String songPath) {
try {
MediaPlayer mp = new MediaPlayer();
mp.setDataSource(this, uri);
mp.prepare();
mp.start();
}
catch (NullReferenceArgument e) {
Log.d(TAG, "NullReferenceException: " + e.getMessage());
}
catch (IllegalStateException e) {
Log.d(TAG, "IllegalStateException: " + e.getMessage());
}
catch (IOException e) {
Log.d(TAG, "IOException: " + e.getMessage());
}
catch (IllegalArgumentException e) {
Log.d(TAG, "IllegalArgumentException: " + e.getMessage());
}
catch (SecurityException e) {
Log.d(TAG, "SecurityException: " + e.getMessage());
}
String url = null;
Object o = myList.get(position);
url = o.toString().replace(" ", "%20").trim();
play = (PlaySongAsy) new PlaySongAsy(url).execute();