Java assertj双容器序列
在比较双精度序列时,如何为assertj指定双精度/浮点公差?这里,Java assertj双容器序列,java,unit-testing,floating-point,precision,assertj,Java,Unit Testing,Floating Point,Precision,Assertj,在比较双精度序列时,如何为assertj指定双精度/浮点公差?这里,items是一个列表,ScoredItem有两个属性itemId和score assertThat(items).extracting("score").containsSequence(3.0, 2.0, 1.0, 0.35, 0.2); 这是在单元测试期间引发异常 java.lang.AssertionError: Expecting: <[3.0, 2.0000000298023224, 1.0, 0.3500
items
是一个列表
,ScoredItem
有两个属性itemId
和score
assertThat(items).extracting("score").containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
这是在单元测试期间引发异常
java.lang.AssertionError:
Expecting:
<[3.0, 2.0000000298023224, 1.0, 0.3500000052154064, 0.20000000298023224]>
to contain sequence:
<[3.0, 2.0, 1.0, 0.35, 0.2]>
…但是没有运气:(因为这是从列表中提取的,所以在调用
containsSequence
之前,您必须使用使用ComparatorForType
调用泛型方法(感谢谁更正了我的颠倒顺序)。然后您可以传入DoubleComparator
assertThat(items)
.extracting("score")
.usingComparatorForType(new DoubleComparator(0.2), Double.class)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
如果items
只是一个double[]
,那么您只需要使用comparatorwithprecision调用方法
assertThat(items)
.usingComparatorWithPrecision(0.5)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
assertThat(items).extracting("score")
.containsSequence(new double[]{3.0, 2.0, 1.0, 0.35, 0.2}, withPrecision(0.5));
或者将第二行的偏移量
替换为精度
assertThat(items)
.usingComparatorWithPrecision(0.5)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
assertThat(items).extracting("score")
.containsSequence(new double[]{3.0, 2.0, 1.0, 0.35, 0.2}, withPrecision(0.5));
我已使用以下代码使用AssertJ 3.9.1对此进行了测试:
public class ScoredItem {
public int itemId;
public double score;
public ScoredItem(int i, double s) {
itemId = i;
score = s;
}
public static void main(String[] args) {
List<ScoredItem> items = new ArrayList<ScoredItem>();
items.add(new ScoredItem(1,3.0));
items.add(new ScoredItem(1,2.0));
items.add(new ScoredItem(1,1.1));
items.add(new ScoredItem(1,0.33));
items.add(new ScoredItem(1,0.22));
assertThat(items)
.extracting("score")
.usingComparatorForType(new DoubleComparator(0.2), Double.class)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
}
}
公共类ScoredItem{
公共int itemId;
公众双倍得分;
公共计分表(整数i,双s){
itemId=i;
得分=s;
}
公共静态void main(字符串[]args){
列表项=新建ArrayList();
添加(新的ScoredItem(1,3.0));
添加(新的ScoredItem(1,2.0));
添加(新的ScoredItem(1,1.1));
添加(新的ScoredItem(1,0.33));
添加(新的ScoredItem(1,0.22));
资产(项目)
.提取(“分数”)
.使用ComparatorForType(新的DoubleComparator(0.2),Double.class)
.容器顺序(3.0,2.0,1.0,0.35,0.2);
}
}
由于这是从列表中提取的,因此在调用containsSequence
之前,必须使用usingComparatorForType
调用泛型方法(感谢谁更正了我的颠倒顺序)。然后您可以传入双比较器
assertThat(items)
.extracting("score")
.usingComparatorForType(new DoubleComparator(0.2), Double.class)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
如果items
只是一个double[]
,那么您只需要使用comparatorwithprecision调用方法
assertThat(items)
.usingComparatorWithPrecision(0.5)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
assertThat(items).extracting("score")
.containsSequence(new double[]{3.0, 2.0, 1.0, 0.35, 0.2}, withPrecision(0.5));
或者将第二行的偏移量
替换为精度
assertThat(items)
.usingComparatorWithPrecision(0.5)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
assertThat(items).extracting("score")
.containsSequence(new double[]{3.0, 2.0, 1.0, 0.35, 0.2}, withPrecision(0.5));
我已使用以下代码使用AssertJ 3.9.1对此进行了测试:
public class ScoredItem {
public int itemId;
public double score;
public ScoredItem(int i, double s) {
itemId = i;
score = s;
}
public static void main(String[] args) {
List<ScoredItem> items = new ArrayList<ScoredItem>();
items.add(new ScoredItem(1,3.0));
items.add(new ScoredItem(1,2.0));
items.add(new ScoredItem(1,1.1));
items.add(new ScoredItem(1,0.33));
items.add(new ScoredItem(1,0.22));
assertThat(items)
.extracting("score")
.usingComparatorForType(new DoubleComparator(0.2), Double.class)
.containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
}
}
公共类ScoredItem{
公共int itemId;
公众双倍得分;
公共计分表(整数i,双s){
itemId=i;
得分=s;
}
公共静态void main(字符串[]args){
列表项=新建ArrayList();
添加(新的ScoredItem(1,3.0));
添加(新的ScoredItem(1,2.0));
添加(新的ScoredItem(1,1.1));
添加(新的ScoredItem(1,0.33));
添加(新的ScoredItem(1,0.22));
资产(项目)
.提取(“分数”)
.使用ComparatorForType(新的DoubleComparator(0.2),Double.class)
.容器顺序(3.0,2.0,1.0,0.35,0.2);
}
}
@Magdop是正确的(除了在断言后使用ComparatorWithPrecision调用)
使用3.10.0,该测试通过:
@Test
public void containsSequence_with_precision() {
// GIVEN
double[] scores = { 3.0, 2.0000000298023224, 1.0, 0.3500000052154064, 0.20000000298023224 };
// THEN
assertThat(scores).containsSequence(new double[] { 3.0, 2.0, 1.0, 0.35, 0.2 }, withPrecision(0.01));
assertThat(scores).usingComparatorWithPrecision(0.01).containsSequence(new double[] { 3.0, 2.0, 1.0, 0.35, 0.2 });
assertThat(scores).usingComparatorWithPrecision(0.01).containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
assertThat(scores).usingComparatorWithPrecision(0.0001).containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
// fails as expected when uncommented
// assertThat(scores).usingComparatorWithPrecision(0.0000000001).containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
}
在断言之前需要调用usingComparatorWithPrecision
,否则AssertJ将不使用它
withPrecision
是偏移量的别名(IMHO可读性稍高)。@Magdop是正确的(除了在断言后使用comparatorwithprecision调用)
使用3.10.0,该测试通过:
@Test
public void containsSequence_with_precision() {
// GIVEN
double[] scores = { 3.0, 2.0000000298023224, 1.0, 0.3500000052154064, 0.20000000298023224 };
// THEN
assertThat(scores).containsSequence(new double[] { 3.0, 2.0, 1.0, 0.35, 0.2 }, withPrecision(0.01));
assertThat(scores).usingComparatorWithPrecision(0.01).containsSequence(new double[] { 3.0, 2.0, 1.0, 0.35, 0.2 });
assertThat(scores).usingComparatorWithPrecision(0.01).containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
assertThat(scores).usingComparatorWithPrecision(0.0001).containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
// fails as expected when uncommented
// assertThat(scores).usingComparatorWithPrecision(0.0000000001).containsSequence(3.0, 2.0, 1.0, 0.35, 0.2);
}
在断言之前需要调用usingComparatorWithPrecision
,否则AssertJ将不使用它
withPrecision
是偏移量的别名(IMHO可读性稍高)。这两种方法对我都不起作用。首先,我没有看到使用ComparatorWithPrecision的(assertj版本3.9.1)。第二个解决方案再次抱怨期望:包含序列:
这两个都不适合我。对于第一个解决方案,我没有看到使用ComparatorWithPrecision
(assertj版本3.9.1)。第二个解决方案再次抱怨期望:包含序列: