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Java 获取twitter的OAuthRequestToken时连接超时_Java_Twitter4j - Fatal编程技术网

Java 获取twitter的OAuthRequestToken时连接超时

Java 获取twitter的OAuthRequestToken时连接超时,java,twitter4j,Java,Twitter4j,嗨,我正在尝试使用以下代码更新twitter状态,但我一直收到以下异常, TwitterException{exceptionCode=[bfb606ed-4ef9708b bfb606ed-4ef97061],状态码=-1,消息=null,代码=-1,retryAfter=-1,rateLimitStatus=null,版本=3.0.3} 我已经把正确的消费者“钥匙”和消费者“秘密”,任何帮助是感激的 public void twitterUpdates(String update)

嗨,我正在尝试使用以下代码更新twitter状态,但我一直收到以下异常, TwitterException{exceptionCode=[bfb606ed-4ef9708b bfb606ed-4ef97061],状态码=-1,消息=null,代码=-1,retryAfter=-1,rateLimitStatus=null,版本=3.0.3}

我已经把正确的消费者“钥匙”和消费者“秘密”,任何帮助是感激的

    public void twitterUpdates(String update) throws TwitterException, IOException  {
    // The factory instance is re-useable and thread safe.
    Twitter twitter = TwitterFactory.getSingleton();
    twitter.setOAuthConsumer("key", "secret");
    RequestToken requestToken = twitter.getOAuthRequestToken();
    AccessToken accessToken = loadAccessToken(twitter.verifyCredentials().getId());
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    while (accessToken == null) {
        System.out
                .println("Open the following URL and grant access to your account:");
        System.out.println(requestToken.getAuthorizationURL());
        System.out
                .print("Enter the PIN(if available) or just hit enter.[PIN]:");
        String pin = br.readLine();
        try {
            if (pin.length() > 0) {
                accessToken = twitter
                        .getOAuthAccessToken(requestToken, pin);
            } else {
                accessToken = twitter.getOAuthAccessToken();
            }
        } catch (TwitterException te) {
            if (401 == te.getStatusCode()) {
                System.out.println("Unable to get the access token.");
            } else {
                te.printStackTrace();
            }
        }
    }
    // persist to the accessToken for future reference.
    storeAccessToken(twitter.verifyCredentials().getId(), accessToken);
    Status status = twitter.updateStatus(update);
    System.out.println("Successfully updated the status to ["
            + status.getText() + "].");


     System.exit(0);
}

根据我个人的经验,这个问题是由防火墙引起的,编码没有问题——我没有解决防火墙问题。
希望这能帮助一些人

根据我个人的经验,这个问题是由防火墙引起的,编码没有问题-我没有解决防火墙问题。
希望这能帮助一些人

您需要增加超时时间

$cb->setConnectionTimeout(20000);
$cb->setTimeout(50000)

您需要增加超时时间

$cb->setConnectionTimeout(20000);
$cb->setTimeout(50000)

我得到了同样的异常,它来自调用
RequestToken RequestToken=twitter.getOAuthRequestToken(callbackURL)
结果是一个与代理相关的问题。通过在ConfigurationBuilder中设置代理主机和端口修复了此问题:

ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true);
cb.setOAuthConsumerKey(key);
cb.setOAuthConsumerSecret(secret);
cb.setHttpProxyHost("proxy");
cb.setHttpProxyPort(8080);
Twitter twitter = new TwitterFactory(cb.build()).getInstance();
注意,我还将callbackURL传递给getOAuthRequestToken方法:

RequestToken requestToken = twitter.getOAuthRequestToken(callbackURL);

我得到了同样的异常,它来自调用
RequestToken RequestToken=twitter.getOAuthRequestToken(callbackURL)
结果是一个与代理相关的问题。通过在ConfigurationBuilder中设置代理主机和端口修复了此问题:

ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true);
cb.setOAuthConsumerKey(key);
cb.setOAuthConsumerSecret(secret);
cb.setHttpProxyHost("proxy");
cb.setHttpProxyPort(8080);
Twitter twitter = new TwitterFactory(cb.build()).getInstance();
注意,我还将callbackURL传递给getOAuthRequestToken方法:

RequestToken requestToken = twitter.getOAuthRequestToken(callbackURL);