Java JPA@OneToMany和@EmbeddedId

我有以下班级（家长）：

子类将主键定义为嵌入id：

@Entity
@Table(name = "PROBE_MONITORS")
public class ProbeMonitor implements Serializable {

    private static final long serialVersionUID = 1L;

    private ProbeMonitorId id;
    private Integer active;

    @EmbeddedId
    @XmlElement
    @JsonProperty
    public ProbeMonitorId getId() {
        return id;
    }
}

当我创建

ProbeCustomer

的实体并尝试调用save方法时（使用

crudepository

） 我得到以下（错误的insert语句）-在insert中有比我在那里写的更多的字段，为了简洁起见，我删除了这些字段：

insert into PROBE_CUSTOMERS (Df_Hostname, Dt_Insert, Df_Customer, Dt_Update, id) values (?, ?, ?, ?, ?)
insert into PROBE_MONITORS (Fl_Active, Dt_Insert, Dt_Update, Df_Customer, Df_Monitor, Df_Type) values (?, ?, ?, ?, ?, ?)
insert into Probe_Monitors (Df_Customer, monitors_Df_Customer, monitors_Df_Monitor, monitors_Df_Type) values (?, ?, ?, ?)

---

我在哪里错误地定义了关系？

不知何故，插入中的字段与映射中的字段不匹配。当所有这些都是出乎意料的时候，很难发现哪些是错误的。在网上我找到了一篇文章，我把@OneToMany简化为@OneToMany（mappedBy=“id.customer”，cascade={CascadeType.all}，fetch=FetchType.LAZY）。这一切都很有效

@Entity
@Table(name = "PROBE_MONITORS")
public class ProbeMonitor implements Serializable {

    private static final long serialVersionUID = 1L;

    private ProbeMonitorId id;
    private Integer active;

    @EmbeddedId
    @XmlElement
    @JsonProperty
    public ProbeMonitorId getId() {
        return id;
    }
}

insert into PROBE_CUSTOMERS (Df_Hostname, Dt_Insert, Df_Customer, Dt_Update, id) values (?, ?, ?, ?, ?)
insert into PROBE_MONITORS (Fl_Active, Dt_Insert, Dt_Update, Df_Customer, Df_Monitor, Df_Type) values (?, ?, ?, ?, ?, ?)
insert into Probe_Monitors (Df_Customer, monitors_Df_Customer, monitors_Df_Monitor, monitors_Df_Type) values (?, ?, ?, ?)