Java 这个代码需要修改一下。
帮助,我需要修改一下这个代码。如何获得65和106的值而不将其从Exercise3 myExer3=新的Exercise3(65106) 基类:Java 这个代码需要修改一下。,java,oop,accessor,Java,Oop,Accessor,帮助,我需要修改一下这个代码。如何获得65和106的值而不将其从Exercise3 myExer3=新的Exercise3(65106) 基类: public class Exercise3 { private int Voltage; private int Resistance; public void setVoltage(int temp){ if (Voltage == 65) Voltage = temp; } public void setResist
public class Exercise3 {
private int Voltage;
private int Resistance;
public void setVoltage(int temp){
if (Voltage == 65)
Voltage = temp;
}
public void setResistance(int temp){
if (Resistance == 106 )
Resistance =106;
}
public int getVoltage (){
return (Voltage);
}
public int getResistance(){
return(Resistance);
}
}
测试等级:
public class Test_Excercise3 {
public static void main(String []args){
Exercise3 myExer3 = new Exercise3(65,106);
System.out.println("Voltage: "+myExer3.getVoltage());
System.out.println("Resistance: "+myExer3.getResistance());
System.out.println("Current : "+ (myExer3.getVoltage()/myExer3.getResistance()));
}
}
这样我就可以得到0.61欧姆或电流的结果。在练习3中添加一个构造函数和正确的设置器,并将结果转换为(双精度)
public class JavaApplication27
{
public static class Exercise3
{
private int voltage;
private int resistance;
public void setVoltage(int v)
{
voltage = v;
}
public void setResistance(int res)
{
resistance = res;
}
public int getVoltage()
{
return voltage;
}
public int getResistance()
{
return resistance;
}
public Exercise3(int v, int res)
{
setVoltage(v);
setResistance(res);
}
public double getCurrent() //helper method :)
{
return (double) getVoltage() / getResistance();
}
}
public static void main(String[] args)
{
Exercise3 myExer3 = new Exercise3(65, 106);
System.out.println("Voltage : " + myExer3.getVoltage());
System.out.println("Resistance: " + myExer3.getResistance());
System.out.println("Current : " + ( (double) myExer3.getVoltage() / myExer3.getResistance())); // Since resistance and voltage are int's, the result of int/int division is int. To get a double) result use (double) :).
System.out.println("Current : " + myExer3.getCurrent()); //you may also use helper method to calculate current
System.out.format( "Current : %.2f", myExer3.getCurrent() ); // to get .61 must use formatter
}
}
输出:
Voltage : 65
Resistance: 106
Current : 0.6132075471698113
Current : 0.6132075471698113
Current : 0.61
您的类需要一个构造函数:
public class Exercise3 {
private int voltage;
private int resistance;
public Exercise3(int voltage, int resistance) {
this.voltage = voltage;
this.resistance = resistance;
}
...
}
有关详细信息,请参阅。在练习3中添加参数化构造函数。@ShadowDroid是的,但我还不知道如何创建构造函数。新手programming@BlackHusky浏览Sajan提供的链接…了解什么是构造函数…然后在代码中实现它..如果出现错误,请顺便编辑问题欢迎使用JAVA Programming for floating point(0.61Ω)使用
double
而不是int
。(但一般来说int更好。)