Java 将txt文件中的数据放入2D数组

非常感谢大家的帮助，两个答案都非常有效。 我有一个Java的实验室助理，我需要一些帮助。
赋值是读取一个包含28个整数的txt，然后将它们放入一个2D数组中。 以下是我所拥有的：

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class TextFileExample {
    public static void main(String[] args) {

        String fileName = "TemperatureData.txt";
        Scanner inputStream = null;
        System.out.println("The file " + fileName + "\ncontains the following lines:\n");
        try
        {
            inputStream = new Scanner(new File("C:\\Users\\username\\Documents\\TemperatureData.txt"));//The txt file is being read correctly.
            String line = inputStream.nextLine();
            String[] numbers = line.split("");
            int[][] temperatures = new int[4][7];
            for (int row = 0; row < 4; row++) {
                for (int column = 0; column < 7; column++) {
                    temperatures[row][column] = temperatures.parseInt(temperatures[row][column]);//Is this correct?
                }
            }
        }
        catch(FileNotFoundException e)
        {
            System.out.println("Error opening the file " + fileName);
            System.exit(0);
        }

        while (inputStream.hasNextLine())
        {
            String line = inputStream.nextLine();
            System.out.println(line);
        }
        inputStream.close();

    }
}

他不要求将txt文件作为输出

txt文件如下所示：

73
71
68
69
75
77
78
76
73
72
72
75
79
76
79
82
84
84
81
78
78
75
72
68
69
65
63
65

应该是

temperatures[row][column] = Integer.parseInt(line);

另外，删除

String[]numbers=line.split（“”）因为它未被使用


你需要重新安排一些事情，这才有效。逻辑是：

Open file
if filenotfound, quit
loop through your arrays
    Parse the string in the file, put it in your array

现在您可以对数组执行一些操作。注意，这并不能很好地处理文件不够长的情况

String fileName = "TemperatureData.txt";
Scanner inputStream = null;
System.out.println("The file " + fileName + "\ncontains the following lines:\n");
try
{
  inputStream = new Scanner(new File("C:\\Users\\username\\Documents\\TemperatureData.txt"));//The txt file is being read correctly.
}
catch(FileNotFoundException e)
{
  System.out.println("Error opening the file " + fileName);
  System.exit(0);
}

for (int row = 0; row < 4; row++) {
  for (int column = 0; column < 7; column++) {
    String line = inputStream.nextLine();
    int[][] temperatures = new int[4][7];
    temperatures[row][column] = Integer.parseInt(line);
  }
}
inputStream.close();

String fileName=“TemperatureData.txt”；
扫描仪输入流=空；
System.out.println（“文件“+fileName+”\n包含以下行：\n”）；
尝试
{
inputStream=new Scanner（新文件（“C:\\Users\\username\\Documents\\TemperatureData.txt”）；//txt文件正在正确读取。
}
catch（filenotfounde异常）
{
System.out.println（“打开文件时出错”+文件名）；
系统出口（0）；
}
用于（int行=0；行<4；行++）{
for（int列=0；列<7；列++）{
String line=inputStream.nextLine（）；
int[][]温度=新int[4][7]；
温度[行][列]=整数.parseInt（行）；
}
}
inputStream.close（）；
这里有一个解决方案：

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
import java.util.StringTokenizer;

public class TxtTo2DArray {
public static void main(String[] args) throws FileNotFoundException, IOException {

    String filename = ""; //Here you must write the path to the file f.exp "//folder//file.txt"

    try{
    FileReader readConnectionToFile = new FileReader(filename);
    BufferedReader reads = new BufferedReader(readConnectionToFile);
    Scanner scan = new Scanner(reads);

    int[][] temperatures = new int[4][7];
    int counter = 0;
    try{
        while(scan.hasNext() && counter < 5){
            for(int i = 0; i < 4; i++){
                counter = counter + 1;
                for(int m = 0; m < 7; m++){
                    temperatures[i][m] = scan.nextInt();
                }
            }
    }

            for(int i = 0; i < 4; i++){
            System.out.println("Temperature at week:" + (i + 1) + " is: " + temperatures[i][0] + ", " + temperatures[i][1] + ", " + temperatures[i][2] + ", " + temperatures[i][3] + ", " + temperatures[i][4] + ", " + temperatures[i][5] + ", " + temperatures[i][6]);

            }

    } catch(InputMismatchException e){
        System.out.println("Error converting number");
    }
    scan.close();
    reads.close();
    } catch (FileNotFoundException e){
        System.out.println("File not found" + filename);
    } catch (IOException e){
        System.out.println("IO-Error open/close of file" + filename);
    }

}     
}

将28个整数转换成2D数组的逻辑是什么。

数据文件是什么样子的？整数是如何分开的？我们假设使用一个包含大量整数的txt文件，每行一个整数。然后将该txt文件写入代码，将num重新输入到4x7数组中，然后打印出数组。请将文本文件编辑到您的帖子中。txt文件错误，每行一个num，总共28行。我刚刚更改了代码。我的问题是，这做了什么，我完成的是温度数组中的数据还是存在更多？我明白了，所以现在我只需要把我的数组做成一个for循环，这样它就可以按需要打印出数组，按行显示所有的数字，对吗？@user2329614是的，但你应该自己做这部分是的，我仍然被卡住了，因为我不确定我在做什么。对Java来说还是新手。我需要使用表格编码还是使用system.out.println（）得到的cna谢谢你的帮助它工作得很好，只是不知道如何说这个问题已经得到了回答。你的意思是什么？：P只是更改循环的问题非常感谢你的帮助。有什么不清楚的吗？如果是，就问吧！如果这回答了您的问题，请接受！：）是的，你回答了我的问题，但是因为我是Java新手，所以我使用了top编码，因为我更了解它。如果你说你更了解durron597发布的代码，那么很难看出你两个都不懂。它们的构造是相同的，只是我的代码有一些额外的异常处理程序。正如我所说的，如果有什么不清楚或你不明白，你可以问！

String fileName = "TemperatureData.txt";
Scanner inputStream = null;
System.out.println("The file " + fileName + "\ncontains the following lines:\n");
try
{
  inputStream = new Scanner(new File("C:\\Users\\username\\Documents\\TemperatureData.txt"));//The txt file is being read correctly.
}
catch(FileNotFoundException e)
{
  System.out.println("Error opening the file " + fileName);
  System.exit(0);
}

for (int row = 0; row < 4; row++) {
  for (int column = 0; column < 7; column++) {
    String line = inputStream.nextLine();
    int[][] temperatures = new int[4][7];
    temperatures[row][column] = Integer.parseInt(line);
  }
}
inputStream.close();

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
import java.util.StringTokenizer;

public class TxtTo2DArray {
public static void main(String[] args) throws FileNotFoundException, IOException {

    String filename = ""; //Here you must write the path to the file f.exp "//folder//file.txt"

    try{
    FileReader readConnectionToFile = new FileReader(filename);
    BufferedReader reads = new BufferedReader(readConnectionToFile);
    Scanner scan = new Scanner(reads);

    int[][] temperatures = new int[4][7];
    int counter = 0;
    try{
        while(scan.hasNext() && counter < 5){
            for(int i = 0; i < 4; i++){
                counter = counter + 1;
                for(int m = 0; m < 7; m++){
                    temperatures[i][m] = scan.nextInt();
                }
            }
    }

            for(int i = 0; i < 4; i++){
            System.out.println("Temperature at week:" + (i + 1) + " is: " + temperatures[i][0] + ", " + temperatures[i][1] + ", " + temperatures[i][2] + ", " + temperatures[i][3] + ", " + temperatures[i][4] + ", " + temperatures[i][5] + ", " + temperatures[i][6]);

            }

    } catch(InputMismatchException e){
        System.out.println("Error converting number");
    }
    scan.close();
    reads.close();
    } catch (FileNotFoundException e){
        System.out.println("File not found" + filename);
    } catch (IOException e){
        System.out.println("IO-Error open/close of file" + filename);
    }

}     
}

Temperature at week:1 is: 73, 71, 68, 69, 75, 77, 78
Temperature at week:2 is: 76, 73, 72, 72, 75, 79, 76
Temperature at week:3 is: 79, 82, 84, 84, 81, 78, 78
Temperature at week:4 is: 75, 72, 68, 69, 65, 63, 65