Java 从listAdapter中提取项目
我从数据库中的JSON文件填充ArrayList,并将它们加载到ListAdapter中。我的代码:Java 从listAdapter中提取项目,java,android,hashmap,listadapter,Java,Android,Hashmap,Listadapter,我从数据库中的JSON文件填充ArrayList,并将它们加载到ListAdapter中。我的代码: private JSONArray mList = null; private ArrayList<HashMap<String, String>> mItemList; ... public void updateJSONdata() { mItemList = new ArrayList<HashMap<String, String>>();
private JSONArray mList = null;
private ArrayList<HashMap<String, String>> mItemList;
...
public void updateJSONdata() {
mItemList = new ArrayList<HashMap<String, String>>();
JSONParser jParser = new JSONParser();
JSONObject json = jParser.getJSONFromUrl(READ_COMMENTS_URL);
try {
mList = json.getJSONArray(TAG_ITEMS_REPORT);
for (int i = 0; i < mList.length(); i++) {
JSONObject c = mList.getJSONObject(i);
// gets the content of each tag
String iName = c.getString(TAG_ITEM_NAME);
...
// creating new HashMap
HashMap<String, String> map = new HashMap<String, String>();
map.put(TAG_ITEM_NAME, iName);
...
// adding HashList to ArrayList
mItemList.add(map);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
现在,我非常确定stringlst
不是提取数据的最优雅、最正确的方法。它确实为单击的每个位置提供了一个正确的字符串,但是所有值显然都包含在一个字符串中。如何一次提取一个值,例如TAG_ITEM_IFNO?谢谢。您可以:
@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
super.onListItemClick(l, v, position, id);
// 1st Approach
HashMap<String, String> map = (HashMap<String, String>) l.getItemAtPosition(position);
Set<Entry<String, String>> entrySet = map.entrySet();
for(Entry<String, String> entry: entrySet) {
String key=entry.getKey();
String value=entry.getValue();
if(key=="your_key_that_you_have_mapped_to_some_textview_in_your_layout") {
// do what you want
}
}
// 2nd Approach
TextView tv=(TextView) v.findViewById(R.id.login_username);
String myvalue=tv.getText().toString();
}
@覆盖
受保护的void onListItemClick(列表视图l、视图v、整数位置、长id){
super.onListItemClick(左、右、位置、id);
//第一种方法
HashMap=(HashMap)l.getItemAtPosition(位置);
Set entrySet=map.entrySet();
for(条目:entrySet){
String key=entry.getKey();
字符串值=entry.getValue();
如果(key==“您的\u key\u您已经\u映射到\u布局中的一些\u textview\u”){
//做你想做的
}
}
//第二种方法
TextView tv=(TextView)v.findviewbyd(R.id.login\u用户名);
字符串myvalue=tv.getText().toString();
}
而不是:
final ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View viewClicked,
int position, long id) {
String lst = mItemList.get(position).toString();
final ListView lv=getListView();
lv.setOnItemClickListener(新的OnItemClickListener(){
@凌驾
公共视图单击(AdapterView父级,视图单击,
内部位置,长id){
String lst=mItemList.get(position.toString();
这对我来说是个骗局
mItemList.get(position).get(value)
编码
@Override
public void onItemClick(AdapterView<?> parent, View viewClicked,
int position, long
Toast.makeText(ReportViewer.this, "Position " + mItemList.get(position).get(TAG_ITEM_COMMENT), Toast.LENGTH_LONG).show();;
Log.d(" ReportView onItemClick", mItemList.get(position).get(TAG_ITEM_COMMENT))
});
}
@覆盖
公共视图单击(AdapterView父级,视图单击,
内位置,长
Toast.makeText(ReportViewer.this,“Position”+mItemList.get(Position).get(TAG_ITEM_COMMENT),Toast.LENGTH_LONG.show();;
Log.d(“ReportView onItemClick”,mItemList.get(position.get(TAG_ITEM_COMMENT))
});
}
你这是什么意思,请详细说明?你使用的是ListActivity
对吗?很抱歉评论不清楚,我误解了你的答案
@Override
public void onItemClick(AdapterView<?> parent, View viewClicked,
int position, long
Toast.makeText(ReportViewer.this, "Position " + mItemList.get(position).get(TAG_ITEM_COMMENT), Toast.LENGTH_LONG).show();;
Log.d(" ReportView onItemClick", mItemList.get(position).get(TAG_ITEM_COMMENT))
});
}