Java加密和Postgres解密(使用pgcrypto模块)
我使用以下代码在Java中进行加密和解密,它似乎工作正常:Java加密和Postgres解密(使用pgcrypto模块),java,postgresql,encryption,cryptography,pgcrypto,Java,Postgresql,Encryption,Cryptography,Pgcrypto,我使用以下代码在Java中进行加密和解密,它似乎工作正常: import javax.crypto.Cipher; import javax.crypto.SecretKey; import javax.crypto.spec.IvParameterSpec; import javax.crypto.spec.SecretKeySpec; import javax.xml.bind.DatatypeConverter; import java.security.SecureRandom; pu
import javax.crypto.Cipher;
import javax.crypto.SecretKey;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
import javax.xml.bind.DatatypeConverter;
import java.security.SecureRandom;
public class MainNew {
public static void main(String[] args) {
String iv = getEncryptionIV();
System.out.println(" iv = "+iv);
String encryptedData= encryptWithIVandKey(iv,encryptionKey,"rakesh.test@eltropy.com");
System.out.println(encryptedData);
String decryptedData = decrypt (iv,encryptionKey,encryptedData);
System.out.println(decryptedData);
}
static final String encryptionKey = "rakesh1@n1111111";
static byte[] doFinal(int encryptMode, SecretKey key, String iv, byte[] bytes) {
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(encryptMode, key, new IvParameterSpec(DatatypeConverter.parseHexBinary(iv)));
byte[] data = cipher.doFinal(bytes);
return data;
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
return null;
}
static SecretKey generateKey(String passphrase) {
SecretKey key = null;
try {
key = new SecretKeySpec(passphrase.getBytes("UTF-8"), "AES");
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
return key;
}
static String getEncryptionIV() {
SecureRandom random = new SecureRandom();
byte[] ivBytes = new byte[16];
random.nextBytes(ivBytes);
return DatatypeConverter.printHexBinary(ivBytes);
}
static String encryptWithIVandKey( String iv, String passphrase, final String strToEncrypt) {
String encryptedStr = "";
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
SecretKey key = generateKey(passphrase);
cipher.init(Cipher.ENCRYPT_MODE, key, new IvParameterSpec(DatatypeConverter.parseHexBinary(iv)));
encryptedStr = DatatypeConverter.printBase64Binary(cipher.doFinal(strToEncrypt.getBytes("UTF-8")));
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
return encryptedStr;
}
static String decrypt(String iv, String passphrase, String ciphertext) {
try {
SecretKey key = generateKey(passphrase);
byte[] decrypted = doFinal(Cipher.DECRYPT_MODE, key, iv, DatatypeConverter.parseBase64Binary(ciphertext));
return new String(decrypted, "UTF-8");
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
return "";
}
}
但当我尝试在postgres中解密生成的加密数据时,出现以下错误:
select convert_from(decrypt_iv('IKMfAng499RNG9viRAreMM5Pmqooidkx76YUBflmzzs=', 'rakesh1@n1111111'::bytea, 'F700FE182F347120F1AE67F5B64E68C2'::bytea, 'aes-cbc/pad:pkcs'),'utf-8') res;
错误:解密_iv错误:数据不是块大小的倍数
当然,当您重新运行Java类时,您会得到一个新的IV——正因为如此,一个新的加密字符串。我认为您从上面注入到PostgreSQL示例中的IV和加密字符串被破坏了。当我运行该类并获得新值时 来自Java的输出: 但这不是真正的问题。。。您必须记住,加密字符串显示为base64编码的字符串。使用解码(文本,文本)来实现。然后,IV以十六进制编码的字符串形式出现。也可以使用解码
iv = CE63BC477D1096B6F38CA77964CBD2CB
pl26CH0sNT8gycZe0FVSVUpwH/moMaFpa6zMtZHcBKQ=
rakesh.test@eltropy.com
select convert_from(
decrypt_iv(
decode('pl26CH0sNT8gycZe0FVSVUpwH/moMaFpa6zMtZHcBKQ=','base64'),
'rakesh1@n1111111'::bytea,
decode('CE63BC477D1096B6F38CA77964CBD2CB','hex'), 'aes-cbc/pad:pkcs'),'utf-8') res;