Java 只有带控件的数字
首先,我是这里的新人。我需要问一个问题Java 只有带控件的数字,java,string,integer,Java,String,Integer,首先,我是这里的新人。我需要问一个问题 Scanner klavye = new Scanner(System.in); System.out.println("DDD-DD-DDDD enter bank number digit: "); String hesapNo = klavye.nextLine(); if(hesapNo.length() != 11) { System.out.println("You need to enter number with 11 digit
Scanner klavye = new Scanner(System.in);
System.out.println("DDD-DD-DDDD enter bank number digit: ");
String hesapNo = klavye.nextLine();
if(hesapNo.length() != 11) {
System.out.println("You need to enter number with 11 digit");
}
else {
if(hesapNo.charAt(3) == '-' && hesapNo.charAt(6) == '-') {
System.out.println(hesapNo + " is valid");
}
else {
System.out.println(hesapNo + " is not valid");
}
}
我只想取数字,但如果我这样写:
ABC-DC-SMND
“计数有效”
我怎样才能解决这个问题
感谢您的关注。这可以通过以下简单方法完成:
您可以使用正则表达式和循环来提示用户直到输入有效
Scanner klavye = new Scanner(System.in);
System.out.println("DDD-DD-DDDD enter bank number digit: ");
String hesapNo;
final String regexPattern = "\\d{3}-\\d{2}-\\d{4}";
do {
hesapNo = klavye.nextLine();
System.out.println("You need to enter a number with 11 digit with pattern: DDD-DD-DDDD");
}
while(!hesapNo.matches(regexPattern));
System.out.println(hesapNo + " is valid");
我认为这是一个学习正则表达式的好机会。看见
Scanner klavye = new Scanner(System.in);
String hesapNo;
boolean validInput;
System.out.println("DDD-DD-DDDD enter bank number digit: ");
do {
hesapNo = klavye.nextLine();
validInput = hesapNo.matches("\\d{3}-\\d{2}-\\d{4}");
if (!validInput) { // if invalid input then warn the user
System.out.println("Your bank number must be in DDD-DD-DDDD format");
}
} while (!validInput); // loop until a valid input is provided
System.out.println(hesapNo + " is valid");
Scanner klavye = new Scanner(System.in);
System.out.println("DDD-DD-DDDD enter bank number digit: ");
String hesapNo;
final String regexPattern = "\\d{3}-\\d{2}-\\d{4}";
do {
hesapNo = klavye.nextLine();
System.out.println("You need to enter a number with 11 digit with pattern: DDD-DD-DDDD");
}
while(!hesapNo.matches(regexPattern));
System.out.println(hesapNo + " is valid");