如何创建类似于JavaBean但具有修改输入的简单逻辑的scala类
我有以下JavaBean如何创建类似于JavaBean但具有修改输入的简单逻辑的scala类,java,spring,scala,Java,Spring,Scala,我有以下JavaBean public class ReportTest { private Integer Impressions; public Integer getImpressions() { return Impressions; } public void setImpressions(String impressions) { Impressions = Integer.parseInt(impressions
public class ReportTest {
private Integer Impressions;
public Integer getImpressions() {
return Impressions;
}
public void setImpressions(String impressions) {
Impressions = Integer.parseInt(impressions.replace(",",""));
}
}
并尝试使用scala类创建一个类似的类,但它抱怨语法错误。看来我不能修改了。我的目的是将scala用作以下项目的Springbean:
Java类很奇怪:
impressions
的getter和setter不使用相同的数据类型。你不可能在一个Scalavar
中把所有的东西都混在一起,它只有一种类型
您可以将Java类转换为等效的Scala代码,如下所示:
class ReportTest {
var _impressions: Int = _
def impressions: Int = _impressions
def impressions_=(v: String): Unit =
_impressions = Integer.parseInt(v.replace(",", ""))
}
但这仍然很奇怪,因为getter和setter的类型不同
在我看来,调用方应该负责将字符串转换为Int
。然后,您的类可以简单地编写为:
class ReportTest {
var impressions: Int = _
}
class ReportTest {
var _impressions: Int = _
def impressions: Int = _impressions
def impressions_=(v: String): Unit =
_impressions = Integer.parseInt(v.replace(",", ""))
}
class ReportTest {
var impressions: Int = _
}