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Java 下拉框_Java_Junit_Selenium - Fatal编程技术网

Java 下拉框

Java 下拉框,java,junit,selenium,Java,Junit,Selenium,我有一个id为PoolsSelect的下拉框。我试图在该下拉框中选择值,但出现错误,以下是我的代码: RenderedWebElement element = (RenderedWebElement) driver.findElement(By.id("PoolsSelect")); RenderedWebElement target = (RenderedWebElement) driver.findElement(By.name("Austria")); element.dragAn

我有一个id为PoolsSelect的下拉框。我试图在该下拉框中选择值,但出现错误,以下是我的代码:

 RenderedWebElement element = (RenderedWebElement) driver.findElement(By.id("PoolsSelect"));
 RenderedWebElement target = (RenderedWebElement) driver.findElement(By.name("Austria"));

 element.dragAndDropOn(target);
我得到的错误是

Error: Unable to find element by name using "PoolsSelect" (7)

我将selenium 2.07a与JUnit 4.8.2一起使用。

您说select的id
PoolsSelect
,但您使用的是By.name选择器。您尝试过按id选择吗?

是的,很抱歉,我应该编辑我使用了by.id,但仍然存在相同的问题这是我尝试过的以下代码driver.findElement(by.xpath(//PoolsSelect”).findElement(by.name(“Austria”).click();