Java菜单在输入后显示两次
嘿,伙计们,在过去的几个小时里,我一直在做这个课程,但似乎无法解决最后两个问题。它基本上是一个稍加修改的收银机类,通过菜单实现基本功能。我遇到的问题是: 1) 在用户第一次选择菜单后,以后每次该菜单在控制台中出现两次,我似乎都找不到解决方法 2) 此外,每当我选择显示收银机的内容时,无论输入如何,第一行始终输出为0.00 下面是我的收银机课程,后面是我的测试人员:Java菜单在输入后显示两次,java,menu,Java,Menu,嘿,伙计们,在过去的几个小时里,我一直在做这个课程,但似乎无法解决最后两个问题。它基本上是一个稍加修改的收银机类,通过菜单实现基本功能。我遇到的问题是: 1) 在用户第一次选择菜单后,以后每次该菜单在控制台中出现两次,我似乎都找不到解决方法 2) 此外,每当我选择显示收银机的内容时,无论输入如何,第一行始终输出为0.00 下面是我的收银机课程,后面是我的测试人员: import java.util.ArrayList; /** * */ /** *@作者科尔 * */ 公营收银机{ p
import java.util.ArrayList;
/**
*
*/
/**
*@作者科尔
*
*/
公营收银机{
private double dailyTotal;
private double totalPrice;
ArrayList<Double> items;
/**
Constructs a cash register with cleared item count and total.
*/
public CashRegister()
{
items = new ArrayList<Double>();
dailyTotal = 0;
totalPrice= 0;
}
/**
Adds an item to this cash register.
@param price the price of this item
*/
public void addItem(double price)
{
items.add(price);
dailyTotal = dailyTotal + price;
}
/**
Gets the price of all items in the current sale.
@return the total amount
*/
public double getTotal()
{
for(int x=0; x<items.size(); x++){
totalPrice = totalPrice + items.get(x);
}
return totalPrice;
}
/**
Gets the number of items in the current sale.
@return the item count
*/
public int getCount()
{
return items.size();
}
/**
Clears the item count and the total.
*/
public void clear()
{
items.clear();
totalPrice = 0;
}
public void display(){
for(int x=0; x<items.size(); x++){
System.out.printf("%10.2f%n", items.get(x));
}
System.out.println("------------------------------");
}
public double getDailyTotal(){
dailyTotal = dailyTotal + totalPrice;
return dailyTotal;
}
导入java.util.Scanner
/**
*
*/
/**
*@作者科尔
*
*/
公共类程序2{
/**
* @param args
*/
public static final String MENU = "******************************************\n" +
"* Enter \"n\" to start a new Cash Register. *\n" +
"* Enter \"a\" to add an item to the current Cash Register. *\n" +
"* Enter \"d\" to display the total of the current Cash Register. *\n" +
"* Enter \"e\" to exit the program. *\n" +
"******************************************";
public static final String NEW_CUSTOMER = "n";
public static final String ADD_ITEM = "a";
public static final String DISPLAY = "d";
public static final String EXIT = "e";
public static void main(String[] args) {
// TODO Auto-generated method stub
CashRegister register = new CashRegister();
Scanner keyboard = new Scanner(System.in);
String input;
double userInput = 0;
do {
input = printMenu(keyboard);
if(input.equals(NEW_CUSTOMER)){
register.getDailyTotal();
register.clear();
}
else if(input.equals(ADD_ITEM)){
System.out.println("Please enter the price of the item: ");
register.addItem(userInput);
userInput = keyboard.nextDouble();
}
else if(input.equalsIgnoreCase(DISPLAY)){
register.display();
System.out.println("Total: " + register.getTotal());
System.out.println("Item Count: " +register.getCount());
}
else if(input.equalsIgnoreCase(EXIT)){
System.out.printf("Daily Sales Total: " + "%.2f%n",register.getDailyTotal());
System.out.println("Program Ended...");
break;
}
}while(input != EXIT);
}
public static String printMenu(Scanner input){ //this method displays the menu for the user
String response = "no reponse yet";
System.out.println(MENU);
response = input.nextLine();
return response; //response returned based on the users input
}
}在添加项目之前,您需要从用户处获得输入,这就是为什么您的第一个项目会获得0。由于您的userInput值在开始时设置为0,并且您的语句被切换,因此您将始终以0.0作为其值初始创建一个项目,而所有其他值都将落后于实际输入一步
else if(input.equals(ADD_ITEM)){
System.out.println("Please enter the price of the item: ");
userInput = keyboard.nextDouble();
register.addItem(userInput);
}
你能告诉我们导致menj出现两次的输入顺序吗?你不能在while中使用==或!=,使用!input.equals(EXIT)logic@RAZ_Muh_Taz很好的捕获,错过了。每当我连续尝试向Cart添加项目时,我都会在userInput=keyboard.nextDouble()之后抛出一个keyboard.nextLine();in:这解决了菜单问题。现在我似乎不明白为什么当我显示所有值时,第一个值总是0.00。非常感谢。如果它确实解决了您的问题,请随意标记为“答案”,这样就结束了问题
else if(input.equals(ADD_ITEM)){
System.out.println("Please enter the price of the item: ");
userInput = keyboard.nextDouble();
register.addItem(userInput);
}