Java 如何更换新线路
不幸的是,我在更换新品时遇到了一些困难Java 如何更换新线路,java,string,Java,String,不幸的是,我在更换新品时遇到了一些困难 public class Example { static String s = "73167176531330624919225119674426574742355349194934\n" + "96983520312774506326239578318016984801869478851843\n" + "85861560789112949495459501737958331952853208805511\n"
public class Example {
static String s = "73167176531330624919225119674426574742355349194934\n" +
"96983520312774506326239578318016984801869478851843\n" +
"85861560789112949495459501737958331952853208805511\n" +
"12540698747158523863050715693290963295227443043557\n" +
"66896648950445244523161731856403098711121722383113\n" +
"62229893423380308135336276614282806444486645238749\n" +
"30358907296290491560440772390713810515859307960866\n" +
"70172427121883998797908792274921901699720888093776\n" +
"65727333001053367881220235421809751254540594752243\n" +
"52584907711670556013604839586446706324415722155397\n" +
"53697817977846174064955149290862569321978468622482\n" +
"83972241375657056057490261407972968652414535100474\n" +
"82166370484403199890008895243450658541227588666881\n" +
"16427171479924442928230863465674813919123162824586\n" +
"17866458359124566529476545682848912883142607690042\n" +
"24219022671055626321111109370544217506941658960408\n" +
"07198403850962455444362981230987879927244284909188\n" +
"84580156166097919133875499200524063689912560717606\n" +
"05886116467109405077541002256983155200055935729725\n" +
"71636269561882670428252483600823257530420752963450".replaceAll("\\n", "");
public static void main(String[] args) {
System.out.println(s);
}
}
我想从字符串s
中删除所有出现的\n
。我试着在StackOverflow上查找答案,但每个帖子似乎都有不同的答案(它们都很复杂,很难记住)
有没有一个简单的方法可以做到这一点
我也试过了
replaceAll("\n", "")
replaceAll("\\\\n", "")
replaceAll(System.getProperty("line.separator"), "")
replaceAll("(\\r|\\n)", "")
首先,当你在做
static String s = "73167176531330624919225119674426574742355349194934\n" +
"96983520312774506326239578318016984801869478851843\n" +
"85861560789112949495459501737958331952853208805511\n" +
"12540698747158523863050715693290963295227443043557\n" +
"66896648950445244523161731856403098711121722383113\n" +
"62229893423380308135336276614282806444486645238749\n" +
"30358907296290491560440772390713810515859307960866\n" +
"70172427121883998797908792274921901699720888093776\n" +
"65727333001053367881220235421809751254540594752243\n" +
"52584907711670556013604839586446706324415722155397\n" +
"53697817977846174064955149290862569321978468622482\n" +
"83972241375657056057490261407972968652414535100474\n" +
"82166370484403199890008895243450658541227588666881\n" +
"16427171479924442928230863465674813919123162824586\n" +
"17866458359124566529476545682848912883142607690042\n" +
"24219022671055626321111109370544217506941658960408\n" +
"07198403850962455444362981230987879927244284909188\n" +
"84580156166097919133875499200524063689912560717606\n" +
"05886116467109405077541002256983155200055935729725\n" +
"71636269561882670428252483600823257530420752963450".replaceAll("\\n", "");
您只替换该字符串的最后一个串联(注意:它没有“\n”
)
您需要做的是去掉字符串声明中的replaceAll
,并在main方法中执行s=s.replaceAll(“\n”,”)代码>如下所示:
public static void main(String[] args) {
s = s.replaceAll("\n", "");
System.out.println(s);
}
测试和工作:D
希望这有帮助:D您可以在打印字符串之前拆分并加入字符串:
public static void main(String[] args) {
System.out.println(String.join("", s.split("\n")));
}
与
"hello" + ("world".replaceAll("o",""))
因此,replaceAll
将只影响字符串的最后一部分,在您的情况下是
"71636269561882670428252483600823257530420752963450".replaceAll("\\n", "").
要解决此问题,请首先使用括号连接所有字符串部分,然后对生成的字符串调用replace
static String s = (
"73167176531330624919225119674426574742355349194934\n" +
"96983520312774506326239578318016984801869478851843\n" +
"85861560789112949495459501737958331952853208805511\n" +
"12540698747158523863050715693290963295227443043557\n" +
"66896648950445244523161731856403098711121722383113\n" +
"62229893423380308135336276614282806444486645238749\n" +
"30358907296290491560440772390713810515859307960866\n" +
"70172427121883998797908792274921901699720888093776\n" +
"65727333001053367881220235421809751254540594752243\n" +
"52584907711670556013604839586446706324415722155397\n" +
"53697817977846174064955149290862569321978468622482\n" +
"83972241375657056057490261407972968652414535100474\n" +
"82166370484403199890008895243450658541227588666881\n" +
"16427171479924442928230863465674813919123162824586\n" +
"17866458359124566529476545682848912883142607690042\n" +
"24219022671055626321111109370544217506941658960408\n" +
"07198403850962455444362981230987879927244284909188\n" +
"84580156166097919133875499200524063689912560717606\n" +
"05886116467109405077541002256983155200055935729725\n" +
"71636269561882670428252483600823257530420752963450"
).replaceAll("\\n", "");
但在我们不处理初始化字段的情况下,我更希望将此“一行”拆分为更多步骤,这些步骤将更具可读性,并且您将避免出现问题中的错误:
//concatenation
String s = "....."
+"....."
:
+".....";
//modification
s = s.replaceAll("\\n","");
试试这个:replace(“\n”和“)代码>也不起作用:(我知道重复的问题不完全相同,但该问题的答案包含在该问题的答案中。实际上,\\n
是正确的,但它在定义字符串时不起作用。请尝试删除它并打印s.replaceAll(\\n“,”)
@ktm5124:这不是私人问题。如果已经有人问过并回答过问题,应该关闭它以减少未来访问者的噪音。@yoseph1998会的。Java中的正则表达式引擎允许我们将\n
写成“\\n”
。要在正则表达式引擎中创建\
文本,我们需要将其写成“\\\\\\\”字符串。“\\”
是regex元字符,可用于生成表示换行符的\n
。我的错是,我将删除commentNice catch。不过最好使用replace
,因为您没有使用regex。@Keppilreplace
也使用regex引擎,但它只是为我们添加了转义机制。它将是d如果我们使用replace(char,char)
,它实际上不使用正则表达式,因为它是简单的迭代。啊,确实如此。那么我没有异议。:)
//concatenation
String s = "....."
+"....."
:
+".....";
//modification
s = s.replaceAll("\\n","");