Java 调用从Hibernate返回记录列表的PL/SQL函数

在尝试调用这样的PL/SQL函数时

type t_messages_rec is record (
   id NUMBER
  ,code VARCHAR2(30)
  ,type VARCHAR2(3)
  ,text VARCHAR2(100)
);
  
type t_messages_tab is table of t_messages_rec;
  
function get_and_clear_messages return t_messages_tab
pipelined;

来自java

import javax.persistence.EntityManager;
import oracle.jdbc.OracleTypes;
import org.hibernate.HibernateException;
import org.hibernate.Session;
import org.hibernate.jdbc.ReturningWork;

// imports are listed for clarity 
    
    ReturningWork work = connection -> {
      try (CallableStatement function = connection.prepareCall("{ ? = call PACKAGE_NAME.get_and_clear_messages() }")) {
        function.registerOutParameter(1, OracleTypes.REF_CURSOR);
        function.execute();

        return function.getResultSet();
      }
    };

    Session session = entityManager.unwrap(Session.class);
    try {
      return (List<Message>) session.doReturningWork(work);
    } catch (HibernateException e) {
      e.printStackTrace();
    }

我怀疑（但我可能错了），这条线

意味着我要将调用的结果存储在“？”变量中，这是流水线函数所不允许的

---

使用Hibernate从管道函数中获取结果的正确方法是什么？

我把它整理好了。显然，可以使用标准sql查询流水线函数：）

例：

Caused by: Error : 6550, Sql = BEGIN :1 := PACKAGE_NAME.get_and_clear_messages() ; END;,
OriginalSql = { ? = call PACKAGE_NAME.get_and_clear_messages() }, 
Error Msg = ORA-06550: line 61, column 12:
PLS-00653: aggregate/table functions are not allowed

  try (CallableStatement function = connection.prepareCall("{ ? = call PACKAGE_NAME.get_and_clear_messages() }")) {

SELECT * FROM PACKAGE_NAME.GET_AND_CLEAR_MESSAGES() m