Java正则表达式-如何以字符串形式获取cbrackets中的所有事件?
我试图从字符串中获取所有事件(cbrackets中的文本和cbrackets) 我试着这样做:Java正则表达式-如何以字符串形式获取cbrackets中的所有事件?,java,regex,Java,Regex,我试图从字符串中获取所有事件(cbrackets中的文本和cbrackets) 我试着这样做: String DATA = "ctrl_interface=/data/misc/wifi/sockets\n" + "driver_param=use_p2p_group_interface=1\n" + "update_config=1\n" + "dev
String DATA = "ctrl_interface=/data/misc/wifi/sockets\n" +
"driver_param=use_p2p_group_interface=1\n" +
"update_config=1\n" +
"device_name=P580_ROW\n" +
"manufacturer=LENOVO\n" +
"model_name=Lenovo \n" +
"model_number=Lenov\n" +
"serial_number=hjhjh7\n" +
"device_type=10-0050F204-5\n" +
"os_version=01020300\n" +
"config_methods=physical_display virtual_push_button\n" +
"p2p_no_group_iface=1\n" +
"\n" +
"network={\n" +
" ssid=\"test1\"\n" +
" psk=\"154695\"\n" +
" key_mgmt=WPA-PSK\n" +
" sim_slot=\"-1\"\n" +
" imsi=\"none\"\n" +
" priority=1\n" +
"}\n" +
"\n" +
"network={\n" +
" ssid=\"test1\"\n" +
" psk=\"154695\"\n" +
" key_mgmt=WPA-PSK\n" +
" sim_slot=\"-1\"\n" +
" imsi=\"none\"\n" +
" priority=1\n" +
"}\n" +
"\n" +
"network={\n" +
" ssid=\"test1\"\n" +
" psk=\"154695\"\n" +
" key_mgmt=WPA-PSK\n" +
" sim_slot=\"-1\"\n" +
" imsi=\"none\"\n" +
" priority=1\n" +
"}\n" +
"\n" +
"network={\n" +
" ssid=\"test1\"\n" +
" psk=\"154695\"\n" +
" key_mgmt=WPA-PSK\n" +
" sim_slot=\"-1\"\n" +
" imsi=\"none\"\n" +
" priority=1\n" +
"}\n" +
"\n" +
"network={\n" +
" ssid=\"SSID2\"\n" +
" psk=\"test123456\"\n" +
" key_mgmt=WPA-PSK\n" +
" sim_slot=\"-1\"\n" +
" imsi=\"none\"\n" +
" priority=19\n" +
"}";
String re1=".*?"; // Non-greedy match on filler
String re2="(\\{.*?\\})"; // Curly Braces 1
List<String> allMatches = new ArrayList<String>();
Pattern p = Pattern.compile(re1 + re2, Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
Matcher m = p.matcher(DATA);
while (m.find()) {
allMatches.add(m.group());
}
for(int i = 0; i < allMatches.size(); i++) {
Logger.d(allMatches.get(i).toString());
}
非常感谢您提供的任何建议如果您只需要获取花括号和里面的内容,您可以尝试以下方法:
// | escaped opening bracket
// | | any character, 0+ times
// | | | closing bracket
// | | | | dot will also match new lines
Pattern p = Pattern.compile("\\{.*?}", Pattern.DOTALL);
Matcher m = p.matcher(DATA);
while (m.find()) {
System.out.println(m.group());
}
使用给定的输入,它将打印:
{
ssid="test1"
psk="154695"
key_mgmt=WPA-PSK
sim_slot="-1"
imsi="none"
priority=1
}
{
ssid="SSID2"
psk="test123456"
key_mgmt=WPA-PSK
sim_slot="-1"
imsi="none"
priority=19
}
注释
- 我在这里所做的基本上就是删除
模式的第一部分,它将匹配“不需要的”文本李>
- 如果您有更复杂的输入,即使用嵌套级别的花括号或花括号中的花括号,那么这将失败(事实上,regex不是解决方案)李>
- 如果您有更复杂的输入,即使用嵌套级别的花括号或花括号中的花括号,那么这将失败(事实上,regex不是解决方案)李>
re1
和re2
?我使用了以下服务:@Mena我想,它对我的情况是否有用?要获取捕获组1中的文本,请使用allMatches.add(m.group(1))代码>。您不必转义}
@redrom,仔细想想,这看起来不像[正确格式化的]JSON,所以正如您所说的,解析器不会有帮助-抱歉。谢谢,它工作起来很有魅力。用于处理的文本很简单,cbrackets中没有内部cbrackets。值得注意的是,原始正则表达式也起作用,只是值在组(1)
中。
{
ssid="test1"
psk="154695"
key_mgmt=WPA-PSK
sim_slot="-1"
imsi="none"
priority=1
}
{
ssid="SSID2"
psk="test123456"
key_mgmt=WPA-PSK
sim_slot="-1"
imsi="none"
priority=19
}