Java Android Viewpager项目访问

我的目标是能够浏览3种不同的布局，并能够单击每个布局上的项目。目前，刷卡工作正常，可以查看所有3种布局

活动：

    public class FetchMenu extends Fetch {

        protected ImageView block;  

        /** Called when the activity is first created. */
         @Override
            public void onCreate(Bundle savedInstanceState) {
                super.onCreate(savedInstanceState);
                setContentView(R.layout.main);

                //pagerviwer

                MyPagerAdapter adapter = new MyPagerAdapter();
                ViewPager myPager = (ViewPager) findViewById(R.id.myfivepanelpager);
                myPager.setAdapter(adapter);
                myPager.setCurrentItem(1); 

                //icon on layout 1

            fbicon = (ImageView)findViewById(R.id.facebookicon);            
            fbicon.setOnTouchListener(new OnTouchListener()
            {

                @Override
                public boolean onTouch(View v, MotionEvent event)
                {
                    Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.facebook.com/pages/Fetch-Training/174358202669554"));
                    startActivity(browserIntent);                   
                    // TODO Auto-generated method stub
                    return false;
                }
           });

页面适配器：

class MyPagerAdapter extends PagerAdapter {

    public int getCount() {
        return 3;
    }

    public Object instantiateItem(View collection, int position) {

        LayoutInflater inflater = (LayoutInflater) collection.getContext()
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);

        int resId = 0;
        switch (position) {
        case 0:
            resId = R.layout.training_topics;
            break;
        case 1:
            resId = R.layout.behaviour_topics;

            break;
        case 2:
            resId = R.layout.tricks_topics;
            break;
        }

        View v = inflater.inflate(resId, null);

        ((ViewPager) collection).addView(v, 0);

        return v;
    }

    @Override
    public void destroyItem(View arg0, int arg1, Object arg2) {
        ((ViewPager) arg0).removeView((View) arg2);

    }

    @Override
    public boolean isViewFromObject(View arg0, Object arg1) {
        return arg0 == ((View) arg1);

    }

    @Override
    public Parcelable saveState() {
        return null;
    }
}

问题： 每个被浏览的布局都包含一组ImageView，如果我在活动中设置代码来侦听这些ImageView的触动，我会得到一个强制关闭错误。我猜活动中的代码不知道ImageView存储在哪个布局中？我读过关于碎片的书，这是我需要的吗

谢谢大家一直都很喜欢帮助

试试这个：

View v = inflater.inflate(resId, null);
ImageView img = v.findviewbyid(R.id.IMAGEID);
// do what you want with the image

将代码放入开关盒中，然后从开关盒返回以获得最佳结果

i、 e:将以下代码移动到每个案例中

    View v = inflater.inflate(resId, null);

    ((ViewPager) collection).addView(v, 0);

    return v;

试试这个：

View v = inflater.inflate(resId, null);
ImageView img = v.findviewbyid(R.id.IMAGEID);
// do what you want with the image

将代码放入开关盒中，然后从开关盒返回以获得最佳结果

i、 e:将以下代码移动到每个案例中

    View v = inflater.inflate(resId, null);

    ((ViewPager) collection).addView(v, 0);

    return v;

---

谢里夫是对的。假设您有两个文本视图。在R.layout.training\u主题布局中。和一个关于R.layout.u主题的图像视图。如果使用PageAdapter，代码应该如下所示

    int resId = 0;
        View v = null;
        switch (position) {
        case 0:
            resId = R.layout.training_topics;
            v = inflater.inflate(resId, null);
            View tv = v.findViewById(R.id.text1);
            View tv2 = v.findViewById(R.id.text2);
            ((TextView)tv).setText("testtesttes");
            ((TextView)tv2).setText("sttesttes2");
            break;
        case 1:
            resId = R.layout.behaviour_topics;
            v = inflater.inflate(resId, null);
            break;
        case 2:
            resId = R.layout.tricks_topics;
            v = inflater.inflate(resId, null);
            View im = v.findViewById(R.id.image1);
            ((ImageView)im).setBackgroundResource(R.drawable.icon);

            break;
        }



        ((ViewPager) collection).addView(v, 0);

        return v;

但不要被我的想法搞糊涂了

    View im = v.findViewById(R.id.image1);
    ((ImageView)im).setBackgroundResource(R.drawable.icon);

你仍然可以使用

    ImageView im = v.findViewById(R.id.image1);
    im.setBackgroundResource(R.drawable.icon);

---

谢里夫是对的。假设您有两个文本视图。在R.layout.training\u主题布局中。和一个关于R.layout.u主题的图像视图。如果使用PageAdapter，代码应该如下所示

    int resId = 0;
        View v = null;
        switch (position) {
        case 0:
            resId = R.layout.training_topics;
            v = inflater.inflate(resId, null);
            View tv = v.findViewById(R.id.text1);
            View tv2 = v.findViewById(R.id.text2);
            ((TextView)tv).setText("testtesttes");
            ((TextView)tv2).setText("sttesttes2");
            break;
        case 1:
            resId = R.layout.behaviour_topics;
            v = inflater.inflate(resId, null);
            break;
        case 2:
            resId = R.layout.tricks_topics;
            v = inflater.inflate(resId, null);
            View im = v.findViewById(R.id.image1);
            ((ImageView)im).setBackgroundResource(R.drawable.icon);

            break;
        }



        ((ViewPager) collection).addView(v, 0);

        return v;

但不要被我的想法搞糊涂了

    View im = v.findViewById(R.id.image1);
    ((ImageView)im).setBackgroundResource(R.drawable.icon);

你仍然可以使用

    ImageView im = v.findViewById(R.id.image1);
    im.setBackgroundResource(R.drawable.icon);