Java SpringBoot-JPA或SQL查询以查找联接表中最常见的项？

我使用Spring Boot、JPA和MySQL创建了一个Spring Boot微服务，它由以下实体关系组成：

Owner can have multiple Cars.
Cars can only have one Owner.

pom.xml：

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.2.5.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>
    <groupId>com.myapi</groupId>
    <artifactId>car-api</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <name>car-api</name>
    <description>Car REST API</description>

    <properties>
        <java.version>1.8</java.version>
    </properties>

    <dependencies>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-data-jdbc</artifactId>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-data-jpa</artifactId>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>

        <dependency>
            <groupId>mysql</groupId>
            <artifactId>mysql-connector-java</artifactId>
            <scope>runtime</scope>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
            <exclusions>
                <exclusion>
                    <groupId>org.junit.vintage</groupId>
                    <artifactId>junit-vintage-engine</artifactId>
                </exclusion>
            </exclusions>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>

</project>

业主地址：

@Repository
public interface OwnerRepository extends JpaRepository<Owner, Long> {
    @Query(value = "SELECT * FROM owner WHERE name = ?", nativeQuery = true)
    Owner findOwnerByName(String name);
}

@Repository
public interface CarRepository extends JpaRepository<Car, Long> {
}

正如你所看到的，汤姆·布雷迪、科比·布莱恩特、魔术师约翰逊都拥有保时捷911。。。那是这个列表中最常见的汽车

在幕后，JPA创建了如下表格：

轿厢台：

CREATE TABLE `car` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `battery_capacity` int(11) NOT NULL,
  `make` varchar(255) DEFAULT NULL,
  `model` varchar(255) DEFAULT NULL,
  `year` varchar(255) DEFAULT NULL,
  `owner_id` bigint(20) NOT NULL,
  PRIMARY KEY (`id`),
  KEY `FK6wxv6hdekqn26n47pb7f1dt02` (`user_id`),
  CONSTRAINT `FK6wxv6hdekqn26n47pb7f1dt02` FOREIGN KEY (`owner_id`) REFERENCES `owner` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;

所有者表：

CREATE TABLE `owner` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `address` varchar(255) DEFAULT NULL,
  `city` varchar(255) DEFAULT NULL,
  `name` varchar(255) NOT NULL,
  `state` varchar(255) DEFAULT NULL,
  `zip_code` int(11) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=11 DEFAULT CHARSET=latin1;

从所有者中选择*：

选择id、用户id、c.make、c.model、c.year FROM cars c

---

JPA或SQL查询甚至可以是一个命名查询，我可以将其放在我的存储库中，该查询将返回最常见汽车的数据，例如Select count*和可能的Group By语句，该语句将表明最常见的汽车是保时捷911s，因为有3个人拥有它们？

声明一个用于持有汽车的类别及其计数

public class CarStatistics {

  private final Car car;
  private final Long count;

  public CarStatistics(Car car, Long count) {
    this.car = car;
    this.count = count;
  }

  public Car getCar() {
    return car;
  }

  public Long getCount() {
    return count;
  }
}

从存储库方法按计数分组和排序返回bean实例：

public interface CarRepository extends JpaRepository<Car, Long> {

  @Query("SELECT new com.example.CarStatistics(c, COUNT(c)) "
      + " FROM Car c "
      + " GROUP BY c.make, c.model "
      + " ORDER BY COUNT(c) DESC")
  List<CarStatistics> findCarCount();
}

调用repository方法并获取结果集中的第一个对象：

@Service
public class CarService {

  private final CarRepository carRepository;

  public CarService(CarRepository carRepository) {
    this.carRepository = carRepository;
  }

  public Car findMostCommonCar() {
    List<CarStatistics> carStatistics = carRepository.findCarCount();
    return carStatistics.get(0).getCar();
  }
}

---

谢谢@Evgeniy Khyst。。。我很快就会试试的。在阅读你的解决方案之前，我发现了一个不同的解决方案。

[
    {
        "id": 1,
        "name": "Tom Brady",
        "cars": [
            {
                "id": 1,
                "make": "Honda",
                "model": "Accord",
                "year": "2020"
            },
            {
                "id": 11,
                 "make": "Nissan",
                 "model": "Maxima",
                 "year": "2019"
            },
            {

                "id": 12,
                "make": "Porsche",
                "model": "911",
                "year": "2017"
            }
        ]
    },
    {
        "id": 2,
        "name": "Kobe Bryant",
        "cars": [
            {
                "id": 2,
                "make": "Porsche",
                "model": "911",
                "year": "2017"
            }
        ]
    },
    {
        "id": 3,
        "name": "Mike Tyson",
        "cars": [
            {
                "id": 3,
                "make": "Volkswagen",
                "model": "Beatle",
                "year": "1973"
            }
        ]
    },
    {
        "id": 4,
        "name": "Scottie Pippen",
        "cars": [
            {
                "id": 4,
                "make": "Ford",
                "model": "F-150",
                "year": "2010"
            }
        ]
    },
    {
        "id": 5,
        "name": "John Madden",
        "cars": [
            {
                "id": 5,
                "make": "Chevrolet",
                "model": "Silverado",
                "year": "2020"
            }
        ]
    },
    {
        "id": 6,
        "name": "Arnold Palmer",
        "cars": [
            {
                "id": 6,
                 "make": "Toyota",
                "model": "Camary",
                "year": "2018"
            }
        ]
    },
    {
        "id": 7,
        "name": "Tiger Woods",
        "cars": [
            {
                "id": 7,
                 "make": "Alfa",
                 "model": "Romeo",
                 "year": "2017"
            }
        ]
    },
    {
        "id": 8,
        "name": "Magic Johnson",
        "cars": [
            {
                "id": 8,
                "make": "Porsche",
                "model": "911",
                "year": "2017"
            }
        ]
    },
    {
        "id": 9,
        "name": "George Foreman",
        "cars": [
            {
                "id": 9,
                "make": "Toyota",
                "model": "Camary",
                "year": "2018"
            }
        ]
    },
    {
        "id": 10,
        "name": "Charles Barkley",
        "cars": [
            {
                "id": 10,
                "make": "Alfa",
                "model": "Romeo",
                "year": "2017"
            }
        ]
    }
]

CREATE TABLE `car` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `battery_capacity` int(11) NOT NULL,
  `make` varchar(255) DEFAULT NULL,
  `model` varchar(255) DEFAULT NULL,
  `year` varchar(255) DEFAULT NULL,
  `owner_id` bigint(20) NOT NULL,
  PRIMARY KEY (`id`),
  KEY `FK6wxv6hdekqn26n47pb7f1dt02` (`user_id`),
  CONSTRAINT `FK6wxv6hdekqn26n47pb7f1dt02` FOREIGN KEY (`owner_id`) REFERENCES `owner` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;

CREATE TABLE `owner` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `address` varchar(255) DEFAULT NULL,
  `city` varchar(255) DEFAULT NULL,
  `name` varchar(255) NOT NULL,
  `state` varchar(255) DEFAULT NULL,
  `zip_code` int(11) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=11 DEFAULT CHARSET=latin1;

+----+----------------+
| id | name           |
+----+----------------+
|  1 | Tom Brady      |
|  2 | Kobe Bryant    |
|  3 | Mike Tyson     |
|  4 | Scottie Pippen |
|  5 | John Madden    |
|  6 | Arnold Palmer  |
|  7 | Tiger Woods    |
|  8 | Magic Johnson  |
|  9 | George Foreman |
| 10 | Charles Barkley|
+----+----------------+

+----------------+--------------+------+
| id | make      | model        | year |
+----+-----------+-----------+---------+
|  1 | Honda     | Accord       | 2020 |
|  2 | Nissan    | Leaf         | 2029 |
|  3 | Volkswagen| Beatle       | 1973 |
|  4 | Porsche   | Taycan       | 2020 |
|  5 | Ford      | F-150        | 2010 |
|  6 | Chevrolet | Silverado    | 2020 |
|  7 | Toyota    | Camry        | 2018 |
|  8 | Chevrolet | Bolt         | 2020 |
|  9 | Honda     | Clarity      | 2018 |
| 10 | Hyundai   | Ioniq        | 2017 |
| 11 | Nissan    | Maxima       | 2019 |
| 12 | Porsche   | 911          | 2020 |
+----+-----------+--------------+------+

public class CarStatistics {

  private final Car car;
  private final Long count;

  public CarStatistics(Car car, Long count) {
    this.car = car;
    this.count = count;
  }

  public Car getCar() {
    return car;
  }

  public Long getCount() {
    return count;
  }
}

public interface CarRepository extends JpaRepository<Car, Long> {

  @Query("SELECT new com.example.CarStatistics(c, COUNT(c)) "
      + " FROM Car c "
      + " GROUP BY c.make, c.model "
      + " ORDER BY COUNT(c) DESC")
  List<CarStatistics> findCarCount();
}

@Service
public class CarService {

  private final CarRepository carRepository;

  public CarService(CarRepository carRepository) {
    this.carRepository = carRepository;
  }

  public Car findMostCommonCar() {
    List<CarStatistics> carStatistics = carRepository.findCarCount();
    return carStatistics.get(0).getCar();
  }
}