Java Hibernate找不到属性的setter（org.Hibernate.PropertyNotFoundException）

我试图在事务类Spring注释中获取SQL查询的结果：

String query = "SELECT DAT, DROP_RADIO FROM My_TABLE";
SQLQuery q = getCurrentSession().createSQLQuery(query);

q.setResultTransformer(Transformers.aliasToBean(CallDrop.class));
List result = q.list();

和CallDrop：

public class CallDrop implements java.io.Serializable {

    private int id;
    private Date dat;
    private BigDecimal onRadio;
    public BigDecimal getOnRadio() {
        return onRadio;
    }
    public void setOnRadio(BigDecimal onRadio) {
        this.onRadio = onRadio;
    }
    public Date getDat() {
        return dat;
    }
    public void setDat(Date dat) {
        this.dat = dat;
    }
}

.hbm.xml是：

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
    <class name="com.company.beans.CallDrop" table="My_TABLE">
        <id name="id" type="int" />

        <property name="dat" type="date">
            <column name="DAT" length="10" />
        </property>
        <property name="onRadio" type="big_decimal">
            <column name="DROP_RADIO" precision="22" scale="0" />
        </property>
</class>
</hibernate-mapping>

我确信我已将hbm.xml添加到会话工厂中的applicationContext文件中：

<bean id="sessionFactoryETL" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
        <property name="dataSource"><ref local="dataSourceETL"/></property>
        <property name="mappingResources">
        <list>
                    <value>com/company/beans/CallDrop.hbm.xml</value>
        </list>
        </property>
        <property name="hibernateProperties">
            <props>
                <prop key="hibernate.dialect">${hibernate.dialect}</prop>
                <prop key="hibernate.show_sql">true</prop>
            </props>
        </property>
    </bean>

所以，没有类型，但它不工作。有人知道问题出在哪里吗？

---

感谢

更改查询以选择DAT作为\DAT\，从My_表中删除\u RADIO as\onRadio\

更改查询以选择DAT作为\DAT\，从My_表中删除\u RADIO as\onRadio\

您可以使用addScalarString columnAlias，键入Type来显式声明本机SQL的列别名：

getCurrentSession().createSQLQuery("select e.id AS id, e.first_name AS firstName, e.password AS password FROM table")
                .addScalar("id", StandardBasicTypes.INTEGER )
                .addScalar("firstName", StandardBasicTypes.STRING )
                .addScalar("password", StandardBasicTypes.STRING )
                .setResultTransformer(Transformers.aliasToBean(Employee.class))
                .list();

---

可以使用addScalarString columnAlias，Type Type显式声明本机SQL的列别名：

getCurrentSession().createSQLQuery("select e.id AS id, e.first_name AS firstName, e.password AS password FROM table")
                .addScalar("id", StandardBasicTypes.INTEGER )
                .addScalar("firstName", StandardBasicTypes.STRING )
                .addScalar("password", StandardBasicTypes.STRING )
                .setResultTransformer(Transformers.aliasToBean(Employee.class))
                .list();

---

您正在映射到kpi_network_bh并通过My_表进行查询。这是错误的吗？这只是发布question@DonRoby这是stackoverflow中的一个新特性：不，我被这个错误绊住了！你能公布确切的例外情况吗？哪个属性导致了异常？您正在映射到kpi_network_bh并通过My_表进行查询。这是错误的吗？发布question@DonRoby这是stackoverflow中的一个新特性：不，我被这个错误绊住了！你能公布确切的例外情况吗？哪个属性导致了异常？