通过在jtextfield中获取字符串,在java中使用LIKE选择所有数据
问题是我找不到合适的字符串,无法在SQL from文本字段中获取类似的术语 **使用此字符串**通过在jtextfield中获取字符串,在java中使用LIKE选择所有数据,java,mysql,netbeans-8,Java,Mysql,Netbeans 8,问题是我找不到合适的字符串,无法在SQL from文本字段中获取类似的术语 **使用此字符串** try{ String Sql ="Select * from learners_info where lrn LIKE %?% "; pst=conn.prepareStatement(Sql); pst.setString(1, txtSearch.getText()); System.out.print(pst);
try{
String Sql ="Select * from learners_info where lrn LIKE %?% ";
pst=conn.prepareStatement(Sql);
pst.setString(1, txtSearch.getText());
System.out.print(pst);
rs = pst.executeQuery();
DefaultTableModel ts = (DefaultTableModel)tableSearch.getModel();
ts.setRowCount(0);
while (rs.next()){
Object searchTable[] = {
rs.getInt("lrn"),
rs.getString("learner_firstname"),
rs.getString("learner_middlename"),
rs.getString("learner_lastname"),
};
ts.addRow(searchTable);
}
}
catch(Exception e){
JOptionPane.showMessageDialog(null, "Invalid info idnumber");
e.printStackTrace();
}
//
finally {
try {
rs.close();
}
catch (Exception e) {
e.printStackTrace();
}
try {
pst.close();
} catch (Exception e) {
e.printStackTrace();
}
try {
} catch (Exception e) {
e.printStackTrace();
}
}
我似乎得到了这个错误:
如果我尝试这个字符串
java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1074)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:988)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:974)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:919)
at com.mysql.jdbc.PreparedStatement.checkBounds(PreparedStatement.java:3813)
at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:3795)
at com.mysql.jdbc.PreparedStatement.setString(PreparedStatement.java:4616)
我使用system.out打印了正在使用的字符串类型,它显示了这一点
此查询可以工作,但似乎不返回任何值
我很抱歉,因为我还不熟悉java中的数据库 从SQL字符串中删除“%”部分。试试这个:
com.mysql.jdbc.JDBC4PreparedStatement@414a0b8f: Select * from learners_info where lrn LIKE '%''1411237''%'
然后尝试在PreparedStatement
setString()
method中传递%s和字符串值,第一次尝试时没有任何撇号,第二次尝试时撇号太多。您可能需要像“%1411237%”这样的
。但是您实际上想要选择什么呢?我想要选择pst.setString(1,txtSearch.getText())中值的所有相似项;其中,该值放在字符串Sql=“Select*from learners\u info where lrn LIKE%?%”中的“?”(问号)处;
String Sql ="Select * from learners_info where lrn LIKE '%'?'%' ";
com.mysql.jdbc.JDBC4PreparedStatement@414a0b8f: Select * from learners_info where lrn LIKE '%''1411237''%'
String Sql ="Select * from learners_info where lrn LIKE ?";