Java程序不会读取字符

这是我当前的代码，我省略了程序的前半部分。我试图使用switch-case语句来确定是否重复while循环，这段代码就在其中。此外，我的IDEEclipse不会将“Asker”识别为变量，也不会让我运行或调试

import java.util.Scanner;

public class Main {
    public static void main(String args[]) {

        int Customers = 1;
        boolean Repeat = true;
        Scanner keyboard = new Scanner(System.in);
        String CustomerInfo[][] = new String[1][6];
        // i = number j = name k = hotel m = location n = date p = discount type
        String CustomerData[][] = new String[1][4];
        // i = stay j = pre cost k = stay length m = final cost
        System.out.println("");
        System.out.println("");
        System.out.println("");
        System.out.println("");
        System.out.println("Welcome to the Northwoods Hotel Reservation System");
        System.out.println("");

        while (Repeat) {

            for (int i = 0; i < Customers; i++) {

                System.out.println("Please Enter Your Name");
                CustomerInfo[i][0] = keyboard.nextLine();
                System.out.println("Please Enter Your Hotel");
                CustomerInfo[i][1] = keyboard.nextLine();
                System.out.println("Please Enter Your Reservation Date");
                CustomerInfo[i][2] = keyboard.nextLine();
                System.out.println("Please Enter The Location");
                CustomerInfo[i][3] = keyboard.nextLine();
                System.out.println("Please Enter Your Room Accomodations");
                CustomerInfo[i][4] = keyboard.nextLine();
                System.out.println("Please Enter Your Discount Type");
                CustomerInfo[i][5] = keyboard.nextLine();

            }    //End I for Loop

            System.out.println("Would you like to add another Customer?? (Y or N)");
            char asker = 'y';
            asker = keyboard.next().charAt(0);

            switch (asker) {

                case 'y':
                case 'Y':
                    Repeat = true;
                case 'n':
                case 'N':
                    Repeat = false;

                default:
                    Repeat = false;

            }    //End switch

        }    //End While
        //System.out.println(Asker);
        System.out.println(Repeat);
        System.out.println(Asker);
        System.out.println("");
        System.out.println("");
        System.out.println("Customer Number\t\t" + "Customer Name \t\t" + "Hotel\t\t" + "Reservation Date \t" + "Accomodations \t" + "Length of Reservation \t" + "Cost" + "Tax \t" + "Discount \t\t" + "Total Cost:");

        for (int i = 0; i < Customers; i++) {
            System.out.println(CustomerInfo[i][0] + " \t" + CustomerInfo[i][1] + " \t" + CustomerInfo[i][2] + " \t" + CustomerInfo[i][3] + " \t" + CustomerInfo[i][4] + " \t" + CustomerInfo[i][5]);

        }    //End For Loop

    }    //End Main Method
}    //End Class

---

阿德尔提供了正确的解决方案：你需要使用break；在你的陈述中

        switch (asker) {

            case 'y':
            case 'Y':
                Repeat = true;
                break; // without a break here, it will fall through
            case 'n':
            case 'N':
                Repeat = false;
                break; // without a break here, it will fall through
                       // but this one isn't as bad since it is the same outcome
            default:
                Repeat = false;

        }    //End switch

---

第一件与您的问题无关的事情是，您没有遵循正确的Java命名约定。变量应该以小写字母开头，所以Asker应该是Asker，等等。其次，您实际上没有指定您的问题是什么。。。您还应该包括代码的前半部分，并提供一个演示该问题的示例。您提到了一个循环，但您发布的代码甚至没有包含一个循环。你期望得到什么结果，而看到的是什么？你需要在switch语句中使用break。Asker是在你的循环之外定义的。main方法也是一个方法，所以你至少在这方面很好。这不是问题，这实际上是int'Asker'@KyleMccoy初始化的位置，而不是根据我看到的。它在switch语句上方三行。