Java org.hibernate.exception.sqlgrammareexception:Table'；XXX和x27；不'；不存在

我将JPA与hibernate实现结合使用。 我的项目如下所示：

我的pom.xml中的依赖项

<dependencies>
    <!-- JUNIT -->
    <dependency>
        <groupId>junit</groupId>
        <artifactId>junit</artifactId>
        <version>3.8.1</version>
        <scope>test</scope>
    </dependency>

    <!-- MYSQL CONNECTOR -->
    <dependency>
        <groupId>mysql</groupId>
        <artifactId>mysql-connector-java</artifactId>
        <version>5.1.9</version>
    </dependency>

    <!-- HIBERNATE -->
    <dependency>
        <groupId>org.hibernate</groupId>
        <artifactId>hibernate-entitymanager</artifactId>
        <version>4.1.6.Final</version>
    </dependency>
    <dependency>
        <groupId>org.hibernate</groupId>
        <artifactId>hibernate-core</artifactId>
        <version>4.1.6.Final</version>
    </dependency>
    <dependency>
        <groupId>org.hibernate</groupId>
        <artifactId>hibernate-annotations</artifactId>
        <version>3.5.5-Final</version>
    </dependency>
    <dependency>
        <groupId>org.hibernate.common</groupId>
        <artifactId>hibernate-commons-annotations</artifactId>
        <version>4.0.4.Final</version>
    </dependency>
    <dependency>
        <groupId>org.slf4j</groupId>
        <artifactId>slf4j-api</artifactId>
        <version>1.7.7</version>
    </dependency>
</dependencies>

我知道数据库中不存在该表，但当我运行应用程序时，我希望在数据库中创建该表

主要方法是：

    public static void main(String[] argv) {
    EntityManagerFactory emf = Persistence.createEntityManagerFactory("manager");
    EntityManager em = emf.createEntityManager();

    EntityTransaction transac = em.getTransaction();

    transac.begin();
    em.persist(new Person("mahmoud", "lotfi", "morroco"));
    transac.commit();

    em.close();
    emf.close();
}

实体人：

@Entity

@表（name=“Person”） 公共类Person实现可序列化{

private static final long serialVersionUID = 4717398914745522714L;

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;

@Column(name = "last_name", length = 50, nullable = false, unique = false, updatable = true)
private String lastname;

@Column(name = "first_name", length = 50, nullable = false, unique = false, updatable = true)
private String firstname;

@Column(name = "country", length = 50, nullable = true, unique = false, updatable = true)
private String country;

public Person(String lastname, String firstname, String country) {
    super();
    this.lastname = lastname;
    this.firstname = firstname;
    this.country = country;
}

public Person() {
}

// GETTERS AND SETTERS ....

---

解决方案摘要

要让

Hibernate

在

persistence.xml

的初始化过程中创建表，必须定义属性

Hibernate.hbm2ddl.auto

。（请参阅：）

属性必须设置为

<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect" 

---

@次优：是的，我知道，但我不知道她为什么没有创建它的alrady existe，PropertiesOrry中的第7行。我一定忽略了两次。：-（请看这里（），可能是解决方案。非常感谢，先生，这是解决方案：）
private static final long serialVersionUID = 4717398914745522714L;

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;

@Column(name = "last_name", length = 50, nullable = false, unique = false, updatable = true)
private String lastname;

@Column(name = "first_name", length = 50, nullable = false, unique = false, updatable = true)
private String firstname;

@Column(name = "country", length = 50, nullable = true, unique = false, updatable = true)
private String country;

public Person(String lastname, String firstname, String country) {
    super();
    this.lastname = lastname;
    this.firstname = firstname;
    this.country = country;
}

public Person() {
}

// GETTERS AND SETTERS ....

<property name="hibernate.hbm2ddl.auto" value="create-drop" />

<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect" 

<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect"