Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/java/366.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Java 整数为双精度并保留小数位数_Java_Formatting_Integer_Double - Fatal编程技术网

Java 整数为双精度并保留小数位数

Java 整数为双精度并保留小数位数,java,formatting,integer,double,Java,Formatting,Integer,Double,如何将int转换为double,但仍保留两位小数? 我的代码,打印一个双精度,但我不知道如何舍入它 System.out.println("Guesses/game = " + ((double) totalguesses / times) / 100); 现在,如果答案是2.333,代码将打印类似的内容,我需要它打印2.33。您可以使用a格式化结果: double avgGuesses = ((double) totalguesses / times) / 100; DecimalForm

如何将
int
转换为
double
,但仍保留两位小数? 我的代码,打印一个双精度,但我不知道如何舍入它

System.out.println("Guesses/game = " + ((double) totalguesses / times) / 100);
现在,如果答案是2.333,代码将打印类似的内容,我需要它打印2.33。

您可以使用a格式化结果:

double avgGuesses = ((double) totalguesses / times) / 100;

DecimalFormat df = new DecimalFormat("#.00");
String avgGuessesFormatted = df.format(avgGuesses);
System.out.println("Guesses/game = " + avgGuessesFormatted);

您可以使用
String.format()

这将打印出结果,小数点后有两位

double yourResult = ...;
String.format("%.2f", yourResult);