Java 如何检索/提取XML元素属性值
我有一个如下所示的XMLJava 如何检索/提取XML元素属性值,java,xml,xml-parsing,Java,Xml,Xml Parsing,我有一个如下所示的XML <?xml version="1.0" encoding="utf-8"?> <PaymentElement> <Payment seqID="3"> <TPayment> <Status>status</Status> </TPayment> </Payment
<?xml version="1.0" encoding="utf-8"?>
<PaymentElement>
<Payment seqID="3">
<TPayment>
<Status>status</Status>
</TPayment>
</Payment>
</PaymentElement>
地位
问题是如何通过java检索/提取seqID值,该值是其中的3
我试过下面的方法,但不起作用
InputStream xml = conn.getInputStream();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(xml);
NodeList list = doc.getElementsByTagName("PaymentElement");
for(int i=0; i<=list.getLength();i++){
NodeList paySeq=doc.getElementsByTagName("Payment seqID");
System.out.println("Payment seqID"+paySeq);
}
InputStream xml=conn.getInputStream();
DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();
DocumentBuilder db=dbf.newDocumentBuilder();
Document doc=db.parse(xml);
NodeList list=doc.getElementsByTagName(“PaymentElement”);
对于(int i=0;i
result
现在应该有3
完整示例
import java.io.*;
import javax.xml.xpath.*;
import org.xml.sax.InputSource;
public class Demo {
public static void main(String[] args) throws Exception {
InputStream inputStream = new FileInputStream("sample.xml");
InputSource inputSource = new InputSource(inputStream);
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile("/PaymentElement/Payment/@seqID");
Object result = expr.evaluate(inputSource, XPathConstants.STRING);
System.out.println(result);
}
}
试一试
输出
Payment seqID = 3
结果为空值3未出现公共静态void main(字符串[]args)引发异常{InputStream xml=new FileInputStream(“sample.xml”);DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();DocumentBuilder db=dbf.newDocumentBuilder();Document doc=db.parse(xml);XPath XPath=XPathFactory.newInstance().newXPath();XPathExpression expr=XPath.compile(“/PaymentElement/Payment/@seqID”);对象结果=expr.evaluate(doc,XPathConstants.STRING);系统.out.println(result);}@RKajaMohideen-+1,我还在您的答案中添加了您的评论的修改版本。我所做的更改是取消对DOM的转换。@BlaiseDoughan,这很好。我只是为他试图解决的问题提供了解决方案。我没有集中精力在DOM部分:-)我在答案中复制粘贴了完整版本,请重试
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new File("1.xml"));
Element e = (Element)doc.getDocumentElement().getElementsByTagName("Payment").item(0);
String id = e.getAttribute("seqID");
System.out.println("Payment seqID = " + id);
Payment seqID = 3