Java 如何使JButton在再次单击时重复其操作？

我试图让“生成”按钮在每次按下时在文本区域中放置一个新词。我尝试过循环，这导致我的GUI停止响应

用户输入示例：单击“生成”按钮3次 文本区域中的示例输出：AppleStatocCumber

有什么建议吗

代码如下：

 public Generator(){
    String[] words = {apple, pear, cucumber, lettuce, tomato, potato};
    String random = (words[new Random().nextInt(words.length)]);

            setBackground(Color.CYAN);
            setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
            setBounds(100, 100, 450, 300);
            contentPane = new JPanel();
            contentPane.setBorder(new EmptyBorder(5, 5, 5, 5));
            setContentPane(contentPane);
            SpringLayout sl_contentPane = new SpringLayout();
            contentPane.setLayout(sl_contentPane);

            JLabel lblNewLabel = new JLabel("Random Word Generator");
            sl_contentPane.putConstraint(SpringLayout.NORTH, lblNewLabel, 10,     SpringLayout.NORTH, contentPane);
            sl_contentPane.putConstraint(SpringLayout.WEST, lblNewLabel, 27, SpringLayout.WEST, contentPane);
            lblNewLabel.setFont(new Font("Tahoma", Font.PLAIN, 21));
            lblNewLabel.setHorizontalAlignment(SwingConstants.CENTER);
            contentPane.add(lblNewLabel);


            JLabel lblInfo = new JLabel("Result will be printed in the white space.");
            sl_contentPane.putConstraint(SpringLayout.NORTH, lblResultsWillBe, 73, SpringLayout.NORTH, contentPane);
            sl_contentPane.putConstraint(SpringLayout.WEST, lblResultsWillBe, 124, SpringLayout.WEST, contentPane);
            lblResultsWillBe.setHorizontalAlignment(SwingConstants.CENTER);
            contentPane.add(lblInfo);

            JTextArea textArea = new JTextArea();
            textArea.setWrapStyleWord(true);
            sl_contentPane.putConstraint(SpringLayout.NORTH, textArea, 150, SpringLayout.NORTH, contentPane);
            sl_contentPane.putConstraint(SpringLayout.WEST, textArea, 141, SpringLayout.WEST, contentPane);
            sl_contentPane.putConstraint(SpringLayout.SOUTH, textArea, 12, SpringLayout.SOUTH, contentPane);
            sl_contentPane.putConstraint(SpringLayout.EAST, textArea, -124, SpringLayout.EAST, contentPane);
            contentPane.add(textArea);

            JButton btnGenerate = new JButton("Generate");
            sl_contentPane.putConstraint(SpringLayout.NORTH, btnGenerate, 41, SpringLayout.NORTH, contentPane);
            sl_contentPane.putConstraint(SpringLayout.WEST, btnGenerate, 163, SpringLayout.WEST, contentPane);
            contentPane.add(btnGenerate);
            btnGenerate.addActionListener(new ActionListener(){
            public void actionPerformed(ActionEvent e) {
                textArea.setText(random);
                Object source = e.getSource();
                if (source == btnGenerate){
                        textArea.setText(random);
                }

            }});
            JLabel txtResults = new JLabel();
            sl_contentPane.putConstraint(SpringLayout.SOUTH, txtResults, -100, 

    SpringLayout.SOUTH, contentPane);
                sl_contentPane.putConstraint(SpringLayout.EAST, txtResults, -143, SpringLayout.EAST, contentPane);
            contentPane.add(txtResults);

        }

文本区域中的示例输出：AppleStatocCumber

不要使用

setText（）

方法。它将替换现有文本

而是使用：

textArea.append(random);

---

因此，每次单击按钮时，新文本都会附加到文本区域。

textArea.setText（textArea.getText（）+random）

也要去掉

对象source=e.getSource（）

；在这种情况下，if语句是不需要的；如果您在actionPerformed（）或其他在事件中被调用的方法中做了错误的事情（从这个角度来看，您可以做的大多数事情都是错误的）。。。你冻结了你的用户界面。你的代码没有编译。我试过了，但是“生成”按钮会重复相同的随机值，并在每次单击时将其添加到以前的值中。例如，用户单击按钮五次，输出为“AppleAppleAppleAppleAppleAppleApple”。我希望每次按下按钮时，该按钮都能将从数组中提取的新随机字符串放入文本区域。@JavaWeenis，您需要在每次单击按钮时确定一个新的随机字符串。因此，随机代码需要放在ActionListener中。