Java JSP ajax json post返回null作为数据

Java JSP ajax json post返回null作为数据,java,jquery,ajax,jsp,servlets,Java,Jquery,Ajax,Jsp,Servlets,当我调用方法request.getParameter(“username”)时,我得到null,为什么我得不到正确的json字符串格式?我也尝试使用JSON.stringify(),但结果是一样的。我希望有人知道出了什么问题 LoginServlet.java package org.SalonNamestaja.Controller.Ajax; import java.io.BufferedReader; import java.io.IOException; import java.io

当我调用方法request.getParameter(“username”)时,我得到null,为什么我得不到正确的json字符串格式?我也尝试使用JSON.stringify(),但结果是一样的。我希望有人知道出了什么问题

LoginServlet.java

 package org.SalonNamestaja.Controller.Ajax;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Enumeration;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.SalonNamestaja.Services.LoginService;
import org.apache.catalina.User;

import com.fasterxml.jackson.databind.ObjectMapper;

/**
 * Servlet implementation class LoginServlet
 */
@WebServlet("/login")
public class LoginServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;
    List<User> users = new LinkedList<User>();

    /**
     * @see HttpServlet#HttpServlet()
     */
    public LoginServlet() {
        super();
        // TODO Auto-generated constructor stub
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        response.setContentType("application/json");
        response.setCharacterEncoding("UTF-8");
        String jsonUsername = request.getParameter("username");
        String jsonPassword = request.getParameter("pass");
        PrintWriter out = response.getWriter();
        out.print("Hello " + jsonUsername + " " + jsonPassword );
    }

}
package org.SalonNamestaja.Controller.Ajax;
导入java.io.BufferedReader;
导入java.io.IOException;
导入java.io.InputStreamReader;
导入java.io.PrintWriter;
导入java.util.Enumeration;
导入java.util.HashMap;
导入java.util.LinkedList;
导入java.util.List;
导入java.util.Map;
导入javax.servlet.ServletException;
导入javax.servlet.annotation.WebServlet;
导入javax.servlet.http.HttpServlet;
导入javax.servlet.http.HttpServletRequest;
导入javax.servlet.http.HttpServletResponse;
导入org.SalonNamestaja.Services.LoginService;
导入org.apache.catalina.User;
导入com.fasterxml.jackson.databind.ObjectMapper;
/**
*Servlet实现类LoginServlet
*/
@WebServlet(“/login”)
公共类LoginServlet扩展了HttpServlet{
私有静态最终长serialVersionUID=1L;
列表用户=新建LinkedList();
/**
*@参见HttpServlet#HttpServlet()
*/
公共LoginServlet(){
超级();
//TODO自动生成的构造函数存根
}
受保护的void doGet(HttpServletRequest请求,HttpServletResponse响应)抛出ServletException,IOException{
}
/**
*@请参阅HttpServlet#doPost(HttpServletRequest请求,HttpServletResponse响应)
*/
受保护的void doPost(HttpServletRequest请求、HttpServletResponse响应)引发ServletException、IOException{
setContentType(“应用程序/json”);
响应。setCharacterEncoding(“UTF-8”);
字符串jsonUsername=request.getParameter(“用户名”);
字符串jsonPassword=request.getParameter(“pass”);
PrintWriter out=response.getWriter();
打印(“Hello”+jsonUsername+“”+jsonPassword);
}
}
login\u user.jsp

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Prijava korisnika</title>
<script src="javascript/jquery-1.11.3.min.js"></script>
<script src="http://code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
<script >
$(document).ready(function(){

    var $name = $('#userName');
    var $pass = $('#password');

    $('#form').submit(function() {

    $.post("/SalonNamestaja/login", {username:$('#userName').val(), pass:$('#password').val()},function(data){
        alert(data);
    });

    });
});
</script>
</head>
<body>

<form id="form" action="/SalonNamestaja/login" method="post">
    Korisnicko ime:<input id="userName" type="text" name="userName"><br>
    Sifra:<input id="password" type="password" name="password"><br>
    <input type="submit" value="Prijavi se">
</form>

<div id="welcometext">
</div>

</body>
</html>

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$(文档).ready(函数(){
变量$name=$(“#用户名”);
var$pass=$(“#密码”);
$('#form')。提交(函数(){
$.post(“/SalonNamestaja/login“,{username:$('#username').val(),pass:$('#password').val()},函数(数据){
警报(数据);
});
});
});
Korisnicko输入法:
西夫拉:

我认为您认为javascript与php一样工作。 当文档准备就绪-当您打开浏览器时,您正在获取变量并发送$.post。我假设你想在提交表格时做这件事。将脚本修改为类似以下内容:

<script>
function sendForm() {
// PUT YOUR CODE HERE
}
</script>

函数sendForm(){
//把你的代码放在这里
}
修改表单时,提交按钮标记应如下所示:

<input type="submit" value="Prijavi se" onclick="sendForm()">


我不确定这是否能解决您的问题,您可以通过迭代
请求来检查是否发送了任何参数。getParameterNames
可能是
多部分/表单数据

尝试注释
@MultipartConfig
和方法
request.getPart()

是否在此处获得所需值:
$(“#用户名”).val()
?您没有返回json响应。尝试文本类型响应。
Text/Text
。当我输入type-response
Text/Text
时,我进入用户名的警报框值,但当它加载登录servlet时,它会再次写入
Hello null