Java 用jaxb覆盖子类中的属性
我有以下XML代码:Java 用jaxb覆盖子类中的属性,java,jaxb,Java,Jaxb,我有以下XML代码: <stereotypes> <stereotype1/> <stereotype2/> </stereotypes> 我需要这个,因为我想以同样的方式对待这些刻板印象: public void someMethod() { for(AbstractStereotype stereotype: getStereotypes()) { System.out.println(stereotype.g
<stereotypes>
<stereotype1/>
<stereotype2/>
</stereotypes>
我需要这个,因为我想以同样的方式对待这些刻板印象:
public void someMethod() {
for(AbstractStereotype stereotype: getStereotypes()) {
System.out.println(stereotype.getPath());
}
}
正如我之前所说,我甚至不确定使用这种方法是否可行 是否希望使用路径属性作为继承指示符?如果是这样,以下内容将有所帮助:
- 堆栈溢出:
- 博客帖子:
我仍然不能100%确定我是否理解您的用例,但以下情况如何: 刻板印象
import java.util.List;
import javax.xml.bind.annotation.XmlElementRef;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Stereotypes {
private List<AbstractStereotype> sterotypes;
@XmlElementRef
public List<AbstractStereotype> getSterotypes() {
return sterotypes;
}
public void setSterotypes(List<AbstractStereotype> sterotypes) {
this.sterotypes = sterotypes;
}
}
1
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Stereotype1 extends AbstractStereotype {
public String getPath() {
return "Path1";
}
}
2
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Stereotype2 extends AbstractStereotype {
public String getPath() {
return "Path2";
}
}
演示
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Stereotypes.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
Stereotypes stereotypes = (Stereotypes) unmarshaller.unmarshal(new File("input.xml"));
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(stereotypes, System.out);
}
}
input.xml
<?xml version="1.0" encoding="UTF-8"?>
<stereotypes>
<stereotype1/>
<stereotype2/>
</stereotypes>
输出
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<stereotypes>
<stereotype1 path="Path1"/>
<stereotype2 path="Path2"/>
</stereotypes>
了解更多信息
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Stereotypes.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
Stereotypes stereotypes = (Stereotypes) unmarshaller.unmarshal(new File("input.xml"));
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(stereotypes, System.out);
}
}
<?xml version="1.0" encoding="UTF-8"?>
<stereotypes>
<stereotype1/>
<stereotype2/>
</stereotypes>
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<stereotypes>
<stereotype1 path="Path1"/>
<stereotype2 path="Path2"/>
</stereotypes>