Java 如何为两名玩家设置掷骰程序
(正在处理)代码没有返回我想要的内容。基本上,有两个玩家,每个玩家轮流掷骰子。这些值应分别存储在变量“p1diceroll”和“p2diceroll”中。它将比较这两个值,并根据谁的得分更高来公布谁将首先得分Java 如何为两名玩家设置掷骰程序,java,processing,dice,Java,Processing,Dice,(正在处理)代码没有返回我想要的内容。基本上,有两个玩家,每个玩家轮流掷骰子。这些值应分别存储在变量“p1diceroll”和“p2diceroll”中。它将比较这两个值,并根据谁的得分更高来公布谁将首先得分 void setup(){ size (100,100); background(200,200,200); println("press l to roll the die!"); } void draw() { if(keyPressed)
void setup(){
size (100,100);
background(200,200,200);
println("press l to roll the die!");
}
void draw() {
if(keyPressed)
keyPressed();
noLoop();
}
void keyPressed(){
int p1diceroll=0;
int p2diceroll=0;
if (key == 'l') {
double rand1 = Math.random();
double rand2 = rand1*6;
double rand3 = rand2 +1;
p1diceroll = (int)rand3;
println("You rolled a " + p1diceroll + "!");
println("player 1! press 'a' to roll");
}
if (key == 'a') {
double rand11 = Math.random();
double rand22 = rand11*6;
double rand33 = rand22 +1;
p2diceroll = (int)rand33;
println("You rolled a " + p2diceroll + "!");
if (p2diceroll>p1diceroll) {
System.out.println("player 2 rolled higher!. They go first. ");
} else if (p2diceroll==p1diceroll) {
System.out.println("It's a tie! player 1 goes first by default." );
} else {
println("player 1 rolled higher! They go first.");
}
}
}
我希望输出是“玩家2滚得更高!他们先走”,“这是平局!默认情况下,玩家1先走”或“玩家1滚得更高。他们先走”。最简单的方法是:
import java.util.Random;
Random rand = new Random();
if (key == 'l'){
// Obtain a number between [0 - 5].
int p1diceroll = rand.nextInt(6) + 1;
println("You rolled a " + p1diceroll + "!");
println("player 2! press 'a' to roll");
}
if (key == 'a'){
// Obtain a number between [0 - 5].
int p2diceroll = rand.nextInt(6) + 1;
然后你就可以像之前那样比较了
请注意,括号中的数字是[0-6]之间的一个区间,包括0和不包括6,我们在后面加上+1得到1-6
即使轮到玩家2,你也会说“玩家1按a滚动”。我在上面给出的代码中对其进行了调整。除了a.a的回答之外,这里还有一些处理选项:
println((int)random(1,7));
(强制转换为int
相当于println(floor(random(1,7));
将浮点数降到floored的1-6之间random()
和调试文本调整后的代码版本:
int p1diceroll=0;
int p2diceroll=0;
String result = "";
void setup(){
size (120,120);
background(200,200,200);
println("press l to roll the die!");
}
void draw() {
background(0);
text("press 'l' for p1"
+"\npress 'a' for p2"
+"\n\np1diceroll: " + p1diceroll
+"\np2diceroll: " + p2diceroll
+"\n\n"+result,5,15);
}
void keyPressed(){
if (key == 'l') {
p1diceroll = (int)random(1,7);
println("You(p1) rolled a " + p1diceroll + "!");
println("player 2! press 'a' to roll");
}
if (key == 'a') {
p2diceroll = (int)random(1,7);
println("You(p2) rolled a " + p2diceroll + "!");
if (p2diceroll > p1diceroll) {
println("player 2 rolled higher(" + p2diceroll + " > " + p1diceroll + ")!. They go first. ");
result = "player 2\ngoes first";
} else if (p2diceroll == p1diceroll) {
println("It's a tie! player 1 goes first by default." );
result = "tie! player 1\ngoes first";
} else {
println("player 1 rolled higher(" + p1diceroll + " > " + p2diceroll + ")! They go first.");
result = "player 1\ngoes first";
}
}
}
我会回答,给我一秒钟,我们需要查看您的其余代码。从这一点上,我无法判断您是否犯了小错误,或者您是否完全不了解编程的工作原理。@JasmineLiao如果这对您有效,请将答案标记为已解决,以便其他人也能看到解决方案。谢谢:)