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一个奇怪的令人沮丧的Java语法错误_Java_Eclipse_Syntax Error - Fatal编程技术网

一个奇怪的令人沮丧的Java语法错误

一个奇怪的令人沮丧的Java语法错误,java,eclipse,syntax-error,Java,Eclipse,Syntax Error,我就是不知道这里出了什么问题,我总是会出错 “标记“=”上的语法错误,此标记后面应为表达式”, 但我无法理解这意味着什么 import java.util.Arrays; public class Zeitmessen { public static void main(String[] args) { int zahl = 1; while (zahl <= 8) { long zeit = System.currentTimeMillis()

我就是不知道这里出了什么问题,我总是会出错 “标记“=”上的语法错误,此标记后面应为表达式”, 但我无法理解这意味着什么

 import java.util.Arrays;

 public class Zeitmessen {

public static void main(String[] args) {

    int zahl = 1;
    while (zahl <= 8) {

        long zeit = System.currentTimeMillis();
        double[][] quicktipp = new double[zahl][6];
        for (int i = 0; i < quicktipp[0].length; i++) {
            double random = (int) (Math.random() * 45);
            zahl++;
            quicktipp = [zahl][6];
            quicktipp[0][i] = random;
            zahl++;
            quicktipp[1][i] = random;
            zahl++;
            quicktipp[2][i] = random;
            zahl++;
            quicktipp[3][i] = random;
            zahl++;
            quicktipp[4][i] = random;
            zahl++;
            quicktipp[5][i] = random;
            zahl++;
            quicktipp[6][i] = random;
            zahl++;
            quicktipp[7][i] = random;






        }

        for (int x = 0; x < quicktipp.length; x++) {
            System.out.println(Arrays.toString(quicktipp[x]));

        }
        zeit = System.currentTimeMillis() - zeit;
        System.out.println(zeit);
        System.out.println("");

        }

}
这里我得到了错误


谁能帮帮我吗?

quicktipp=[zahl][6]没有任何意义。我怀疑您认为需要在该点或其他位置初始化数组,但您没有,您已经使用
double[][]quicktipp=new double[zahl][6]进行了初始化。因此,您可以直接删除该行并转到
quicktipp[0][i]=random代码。

数组=[1][6];是无效的java。我很好奇:你期望那行代码做什么?你的意图是什么?(代码中可能也有逻辑错误,但那是语法错误。)
     quicktipp = [zahl][6];