情况不正常。Java,AWT
我正在用AWT在Java编写一个小的登录表单。在检查用户输入登录时遇到一个问题:我需要,当用户输入“admin”作为登录名,输入“password”作为密码时,程序输出“success!”,但无论如何,即使输入的数据满足条件,我也会收到“error!”消息 那么,我应该怎么做才能让程序正确地检查条件呢 代码: 试试情况不正常。Java,AWT,java,if-statement,awt,Java,If Statement,Awt,我正在用AWT在Java编写一个小的登录表单。在检查用户输入登录时遇到一个问题:我需要,当用户输入“admin”作为登录名,输入“password”作为密码时,程序输出“success!”,但无论如何,即使输入的数据满足条件,我也会收到“error!”消息 那么,我应该怎么做才能让程序正确地检查条件呢 代码: 试试.equals()而不是= import java.awt.*; import java.awt.event.*; import javax.swing.*; public cla
.equals()
而不是=
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class Login extends JFrame {
private JButton button = new JButton("Confirm");
private JLabel label1 = new JLabel("Login:");
private JTextField login = new JTextField("", 8);
private JLabel label2 = new JLabel("Password:");
private JTextField pswrd = new JTextField("", 8);
public Login() {
super("Please log in");
this.setBounds(100, 100, 250, 100);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
Container container = this.getContentPane();
container.setLayout(new GridLayout(3,2,2,2));
container.add(label1);
container.add(label2);
container.add(login);
container.add(pswrd);
button.addActionListener(new ButtonEvent());
container.add(button);
}
class ButtonEvent implements ActionListener {
public void actionPerformed(ActionEvent e) {
if (login.getText() == "admin" && pswrd.getText() == "password")
{
JOptionPane.showMessageDialog(null, "Succes!", "Output", JOptionPane.PLAIN_MESSAGE);
}
else
{
JOptionPane.showMessageDialog(null, "Wrong!", "Output", JOptionPane.PLAIN_MESSAGE);
}
}
}
public static void main(String[] args) {
Login app = new Login();
app.setVisible(true);
}
}