Java 当我点击"；“完成”；数字键盘上的按钮

我有以下代码：

    final EditText edC = (EditText) findViewById(R.id.etC);
    final String creditsS = edC.getText().toString().trim();
    final TextView tvD = (TextView) findViewById(R.id.tvDisplay); 

    tvD.setText("Enter amount of credits");

    edC.setOnEditorActionListener(new OnEditorActionListener() {

        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            int credits = Integer.parseInt(creditsS);
            if (actionId == EditorInfo.IME_ACTION_DONE) {
                tvD.setText("Your amount of credits" + credits);
                return true;
            }
            return false;
        }
    });

当我点击“完成”按钮时，应用程序崩溃了。我不明白问题出在哪里。请帮忙？谢谢

将代码更改为：

final EditText edC = (EditText) findViewById(R.id.etC);
final TextView tvD = (TextView) findViewById(R.id.tvDisplay); 

tvD.setText("Enter amount of credits");

edC.setOnEditorActionListener(new OnEditorActionListener() {

    @Override
    public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
        String creditsS = edC.getText().toString().trim();
        int credits = Integer.parseInt(creditsS);
        if (actionId == EditorInfo.IME_ACTION_DONE) {
            tvD.setText("Your amount of credits" + credits);
            return true;
        }
        return false;
    }
});

---

它崩溃是因为你在没有任何值之前就从edC获取了值，所以它试图解析一个空字符串，结果由于NumberFormatException而崩溃。

日志猫怎么说？请发布一个日志猫。你仍然应该更好地对待用户键入的内容，你仍然可以得到

NumberFormatException

。别忘了把答案标为正确。