Java 为什么try-catch最终没有重新提示用户？

我对Java和所有编程都比较陌生。我正在为学校写一个简单的猜测数字程序。用户输入数字1-10，并将其与随机数字1-10进行比较。req规范规定，应检查所有无效输入，如果发现无效输入，应重新提示用户。为此，我正在使用try-catch-finally。如果int guess确实不是整数，我的catch块将查找该异常，但它不会重新提示用户，而是保留初始值0。我只是在用户输入之前初始化了猜测，因为终端反复对我大喊大叫，直到我这么做。我也不确定为什么必须在try块之前初始化变量

我到处寻找，但我发现的每个解决方案的代码在结构上都与我的几乎相同。我猜这一定是我不熟悉/其他人忽略了提及的东西，因为它太简单了。顺便说一下，这是我第一次使用try-catch-finally

int guess = 0;
int number = (int)((Math.random()*10) + 1);
System.out.print("Please guess a number between 1 and 10, inclusive: ");

//open try
try(BufferedReader br = new BufferedReader(new InputStreamReader(System.in))) {

  guess = Integer.parseInt(br.readLine());

  //monitor input
  while(guess < 1 || guess > 10) {//open while

    System.out.print("You seem to have entered something wrong. Please only");
    System.out.println(" enter ");
    System.out.print("an integer number between 1 and 10, 1 and 10 included: ");
    guess = Integer.parseInt(br.readLine());

  }//close while

  //close try
} catch(NumberFormatException e) {//open catch

  System.out.print("You seem to have entered something wrong.  Please only");
  System.out.println(" enter ");
  System.out.print("an integer number between 1 and 10, 1 and 10 included: ");

  //close catch
} finally {//open finally

  //user feedback
  if(number == guess){

    System.out.println("You got it! You guessed the number correctly. It is "
    + number + ".");

  } else {

    System.out.println("I'm sorry! That is not the number I was thinking of.");
    System.out.println("You guessed " + guess + ", but the number is "
    + number + ".");

  }
}//close finally

---

从

parseInt

引发的异常会导致循环中断。您可能希望您的循环包含try-catch-finally子句，而不是try-catch-finally子句。

不管异常与否，finally部分都会发生。

---

您应该将finally部分的代码放在try部分。

您应该首先组织代码，正如其他人所说，您应该在try中执行代码并处理catch上的异常，如果您要在try块中执行，那么最后是多余的。举个例子，你还有另外一个问题，他们比我解释得更好。希望有帮助。 [连结]

---

另外，当你输入一个数字时，NumberformatException也会起作用，但我认为你错过了IOException。

如果你不输入一个数值，你会被异常抛出循环。你应该在while循环中捕获异常。非常感谢你的输入。我一起删除了finally块，因为这对我来说是不必要的。我将不得不仔细阅读异常类型。。。感谢您的输入，我添加了第二个catch块来捕获IOExceptions。这个词“break”让我思考，我将它全部放入while循环，就像您所说的，并在catch块的末尾添加了一些continue语句。请参考编辑的原始帖子，如果您知道为什么需要continue语句，以及它如何真正影响循环流，请告诉我对不起，我刚刚做了。现在，它在原始帖子的末尾被编辑。我是这个平台的新手，所以我不知道添加第二块代码是否是非正式的/违反规则的。我不认为有必要使用

continue

语句。尝试调试程序以查看差异。如果你没有成功，那么也许你应该把它作为一个单独的问题发布。我只是简单地删除了它们，所有这些都起了作用。。。也许我之前错过了一个支架什么的。非常感谢你的帮助

    //init vars needed
    int guess;
    int number = (int)((Math.random()*10) + 1);
    boolean done = false;
    System.out.print("Please guess a number between 1 and 10, inclusive: ");

    while(!done) {//open while
      try {//open try
        guess = Integer.parseInt(br.readLine());

        while(guess < 1 || guess > 10) {
          System.out.print("You seem to have entered something wrong. Please only");
          System.out.println(" enter ");
          System.out.print("an integer number between 1 and 10, 1 and 10 included: ");
          guess = Integer.parseInt(br.readLine());
        }

        if(number == guess) {
          System.out.println("You got it! You guessed the number correctly. It is "
          + number + ".");
        } else if(number != guess) {
          System.out.println("I'm sorry! That is not the number I was thinking of.");
          System.out.println("You guessed " + guess + ", but the number is "
          + number + ".");
        }

        done = true;
      } //close try

      catch(NumberFormatException e) {//open catch
        System.out.print("You seem to have entered something wrong. Please only");
        System.out.println(" enter ");
        System.out.print("an integer number between 1 and 10, 1 and 10 included: ");
        continue;
      }//close catch

      catch(IOException e) {//open catch
        System.out.print("You seem to have entered something wrong. Please only");
        System.out.println(" enter ");
        System.out.print("an integer number between 1 and 10, 1 and 10 included: ");
        continue;
      }//close catch

    }//close while

    try {
        System.out.println("Im the try block");
    }
    finally {
        System.out.println("Im the finally block");
    }

Output:

Im the finally block 
Im the try block